Scala Regex Match And Replace

Question

I want to find a pattern """("\"\{.*?\}\"")""" in a string and drop "{ and }" from the start and the end respectively from all instances of the pattern found in the string.

For example: "batters": "{{"id":"1001"}}" should be replaced by "batters": {"id":"1001"}

Is there any Regex function that can help me?

Something like """\"batters\": \"{{\"id\":\"1001\"}}\"""".replaceAll("""\"{(.*?)}\"""", "$1")? — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 28, 2015 at 15:16
Hey, @stribizhev, you may forget to escape { in """\"{(.*?)}\"""", java.util.regex.PatternSyntaxException is thrown when running the code. — Allen Chou
– Allen Chou, Commented Jul 28, 2015 at 15:55

Allen Chou · Accepted Answer · 2015-07-28 15:50:39Z

1

Happen to see a detailed explanation about this usage of regular expression in JavaScript: The Definitive Guide 6th Edition 10.2 String Methods for Pattern Matching

Recall that parenthesized subexpressions of a regular expression are numbered from left to right and that the regular expression remembers the text that each subexpression matches. If a $ followed by a digit appears in the replacement string, replace() replaces those two characters with the text that matches the specified subexpression

scala> """"{{"id":"1001"}}"""".replaceAll("""\"\{(.*?)\}\"""", "$1")
res15: String = {"id":"1001"}

The code above should solve you problem.

edited Jul 28, 2015 at 15:50

answered Jul 28, 2015 at 15:35

Allen Chou

1,2371 gold badge9 silver badges12 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Scala Regex Match And Replace

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related