I have a string similar to "dasdasdsafs[image : image name : image]vvfd gvdfvg dfvgd". From this string, I want to remove the part which stars from [image : and ends at : image] . I tried to find the 'sub-string' using following code-
result = re.search('%s(.*)%s' % (start, end), st).group(1)
but it doesn't give me the required result. Help me to find the correct way to remove the sub-string from the string.
You can use re.sub :
>>> s='dasdasdsafs[image : image name : image]vvfd gvdfvg dfvgd'
>>> re.sub(r'\[image.+image\]','',s)
'dasdasdsafsvvfd gvdfvg dfvgd'
The obvious problem will be that you can't just plug in an arbitrary string, because it will contain characters that will change how re looks at it. Instead, you want to escape your start and end strings. Of course, you could just fix them manuall by typing in the correct escape code this time, but it would be better if there were an easy way to have the python library do it for you, and handle any values.
import re
start = re.escape("[image : ")
end = re.escape(" : image]")
st = "dasdasdsafs[image : image name : image]vvfd gvdfvg dfvgd"
result = re.search('%s(.*)%s' % (start, end), st).group(1)
print result
You probably just need to escape the square brackets since those are special characters in regex (i.e, start = r"\[image :" and end = r": image\]").
result = re.search('%s(.*)%s' %(start, end),st).group(1) and it returns me the string between from the start and end. But i need to remove from start to end.This will remove all occurrences in a string
import re
s = "dasdasdsafs[image : image name : image]vvfd gvdfvg dfvgd"
s = re.sub(r'\[image :.*?: image\]', r'', s)
