How to make random string replace textview?

Question

I have an activity with 3 edittexts and a button. I have a second activity with 2 textviews.

When button is clicked i want two random edittexts values from activity1 to replace the text on textviews on activity2.

I managed to do that, but not randomly. How can I make it random?

Here is the first activity.

final EditText et  = (EditText) findViewById(R.id.editText);
        final EditText et1 = (EditText) findViewById(R.id.editText2);
        final EditText et2 = (EditText) findViewById(R.id.editText3);
        Button btn = (Button) findViewById(R.id.button);

        btn.setOnClickListener(new View.OnClickListener() {

            public void onClick (View v){
                Intent i = new Intent(MainActivity.this, postavke.class);
                i.putExtra("prvi", et.getText().toString());
                i.putExtra("drugi", et1.getText().toString());
                i.putExtra("treci", et2.getText().toString());
                startActivity(i);
            }
        });
    }

Here is the second activity.

   TextView tv = (TextView) findViewById(R.id.asdf);
    tv.setText(getIntent().getExtras().getString("prvi"));

TextView dr = (TextView) findViewById(R.id.asdg);
dr.setText(getIntent().getExtras().getString("drugi"));

I think he has 2 slots, 3 values and wants to use 2 of the 3 values, randomly selected — Tim
– Tim, Commented Sep 28, 2015 at 10:01

JoeyJubb · Accepted Answer · 2015-09-29 13:02:37Z

2

In your second activity:

String[] texts = new String[]{
    getIntent().getExtras().getString("prvi"),
    getIntent().getExtras().getString("drugi"),
    getIntent().getExtras().getString("treci"),
};

TextView tv = (TextView) findViewById(R.id.asdf);
TextView dr = (TextView) findViewById(R.id.asdg);

Random random = new Random();
tv.setText(texts[random.nextInt(3)]);
dr.setText(texts[random.nextInt(3)]);

Or, for unique values:

First activity:

final EditText et  = (EditText) findViewById(R.id.editText);
    final EditText et1 = (EditText) findViewById(R.id.editText2);
    final EditText et2 = (EditText) findViewById(R.id.editText3);
    Button btn = (Button) findViewById(R.id.button);

    btn.setOnClickListener(new View.OnClickListener() {

        public void onClick (View v){

            ArrayList<String> texts = new ArrayList<>();
            texts.add(et.getText().toString());
            texts.add(et1.getText().toString());
            texts.add(et2.getText().toString());

            Intent i = new Intent(MainActivity.this, postavke.class);
            i.putExtra("texts", texts);
            startActivity(i);
        }
    });
}

Second activity:

ArrayList<String> texts = getIntent().getExtras().getStringArrayList("texts");

TextView tv = (TextView) findViewById(R.id.asdf);
TextView dr = (TextView) findViewById(R.id.asdg);

Collections.shuffle(texts);
tv.setText(texts.get(0));
dr.setText(texts.get(1));

edited Sep 29, 2015 at 13:02

answered Sep 28, 2015 at 10:05

JoeyJubb

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6 Comments

pouyan Over a year ago

it is possible that random number generate same number . it is better that just create a random number and delete it s index from array like this: texts.remove[random.nextInt(3)]]; and then use other texts array elements.

Tim Over a year ago

This should work, but there is a 33% chance the strings will be the same

JoeyJubb Over a year ago

Just posted the simplest answer! There was no mention of wanting them to be unique

Tomo Over a year ago

@JoeFrostick Thanks for the code, yesterday it was fine, but today i realised Tim Castelijns was right, I do need them to be unique. Could you please edit the code so that one string doesn't show twice on the screen in the same time? Sorry that I didn't pay attention earlier.

JoeyJubb Over a year ago

I've updated the answer. The new answer also shows how you could send the array list as a while, reducing the number of argument values you need to remember

|

Don Chakkappan · Accepted Answer · 2015-09-28 10:05:25Z

0

Add your Strings(Eg : getIntent().getExtras().getString("prvi")) from previous Activity to a ArrayList.

Then do simply Collection.shuffle(your_list);

Get items from ArrayList & set it to your TextViews.

answered Sep 28, 2015 at 10:05

Don Chakkappan

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Comments

nbokmans · Accepted Answer · 2015-09-28 10:09:13Z

Declare an array that will contain the values:

public String[] randomAnswers = new String[3]; //3 because you said you have 3 random strings

In your onCreate() add the values to the array: randomAnswers[0] = getIntent().getExtras().getString("prvi"); randomAnswers[1] = getIntent().getExtras().getString("drugi"); randomAnswers[2] = getIntent().getExtras().getString("treci");
Select two random values:

private static final Random RANDOM = new Random(); //in java.util package

Inside onCreate:

final int randomInt1 = RANDOM.nextInt(3); //nextInt(int) goes from 0 to int-1, considering arrays start at index=0 we want to get a random number from: 0, 1, 2
int randomInt2;
do {
        randomInt2 = RANDOM.nextInt(3);
} while (randomInt1 == randomInt2);
final String firstRandomString = values[randomInt1];
final String secondRandomString = values[randomInt2];`

pouyan · Accepted Answer · 2015-09-28 10:16:52Z

0

you can use some thing like this the edited form of @Joe Frostick answere:

String[] texts = new String[]{
getIntent().getExtras().getString("prvi"),
getIntent().getExtras().getString("drugi"),
getIntent().getExtras().getString("treci"),
                             };

TextView tv = (TextView) findViewById(R.id.asdf);
TextView dr = (TextView) findViewById(R.id.asdg);

Random random = new Random();
texts.remove(random.nextInt(3));
tv.setText(texts[0]);
dr.setText(texts[1]);

answered Sep 28, 2015 at 10:16

pouyan

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Comments

Tomo · Accepted Answer · 2015-09-28 11:40:51Z

0

Thanks for the help everyone, I really didn't expect so many answers in not much time. You're the best!

answered Sep 28, 2015 at 11:40

Tomo

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1 Comment

Fundhor Over a year ago

That's the point of StackOverflow. All fo us also post questions one day or another. And trying to answer questions is a good way to learn new features ;) hava a ncie day

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