underscore.js with two arrays

Question

I have the following array:

['aaa', 'bbb', 'ccc', 'ddd']

My goal is to remove from it unexpected values:

I tried to do it with underscore without function like below:

_.without(['aaa', 'bbb', 'ccc', 'ddd'], 'bbb', 'ccc');

It works fine, but unfortunately it does not work with array:

_.without(['aaa', 'bbb', 'ccc', 'ddd'], ['bbb', 'ccc']);

I've googled a bit and find the post underscore.js - Is there a function that produces an array thats the difference of two arrays?

But in my case this one also does not work, namely it returns somthing like that:

"a","a","a"

when I tired to use apply function.

Can some one suggest what need to be done to remove all unexpected keys with array?

gen_Eric · Accepted Answer · 2015-09-29 18:22:56Z

4

Have you tried _.difference?

_.difference(['aaa', 'bbb', 'ccc', 'ddd'], ['bbb', 'ccc']);

answered Sep 29, 2015 at 18:22

gen_Eric

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1 Comment

fashuser Over a year ago

Thanks for answer. Accepted. Before,I've briefly tried the following function. But actually I was a bit surprised why the following example _.difference([1, 2, 3, 4, 5], [5, 2, 10]); skip 10. But now I see that it is described in the documentation.

raina77ow · Accepted Answer · 2015-09-29 18:27:37Z

1

For the sake of completeness, that's how it can be done with _.without:

var source = ['aaa', 'bbb', 'ccc', 'ddd'];
var blacklist = ['bbb', 'ddd'];
var without = _.without.apply(_, [source].concat(blacklist));

answered Sep 29, 2015 at 18:27

raina77ow

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