I'm obtaining input values in a list using the following statement:
ar = map(int, raw_input().split())
However, I would want to limit the number of inputs a user can give at a time. For instance, if the limit is specified by a number n, the array should only capture the first n values entered during the program.
e.g: if n = 6, Input:
1 2 3 4 5 6 7 8 9 10
On performing 'print ar', it should display the following without any error messages:
[1, 2, 3, 4, 5, 6]
If you want to ignore the rest of the input, then you can use slicing to take only the first n input. Example -
n = 6
ar = map(int, raw_input().split(None, n)[:n])
We are also using the maxsplit option for str.split so that it only splits 6 times , and then takes the first 6 elements and converts them to int.
This is for a bit more performance. We can also do the simple - ar = map(int, raw_input().split())[:n] but it would be less performant than the above solution.
Demo -
>>> n = 6
>>> ar = map(int, raw_input().split(None, n)[:n])
1 2 3 4 5 6 7 8 9 0 1 2 3 4 6
>>> print ar
[1, 2, 3, 4, 5, 6]
n results.How about indexing ar to just the 6th element? Technically, it's to the 7th element, as newarray will slice up to, but not including nth element
ar = map(int, raw_input().split())
print ar
#[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
newarray=ar[0:6]
print newarray
#[1, 2, 3, 4, 5, 6]
This should allow for unlimited input
I was looking for a solution to the same question.
I figured out what I can do below is my solution.
bookid = []
M = int(input())
S = input().split()
for i in range(M):
books.append(S[i])
print(booksid)
But I think it's definitely not the most effective way to do it but easy.
