PHP Includes/Require in a function with variable for path

Question

I am trying to set things up so when we create a testing folder, I can easily change the path to an important file in various places. But, running into an issue.

$folder = "/test";

function foo(){
global $folder;
require_once($_SERVER['DOCUMENT_ROOT'].$folder."/order/includes/db.php");
..do stuff

}

Does not work

function foo(){
require_once($_SERVER['DOCUMENT_ROOT']."/test/includes/db.php");
..do stuff
}

Does work

What am I missing?

/order/ is missing in the second snippet (the working one)

GrafiCode
– GrafiCode

2015-10-14 18:48:00 +00:00
Commented Oct 14, 2015 at 18:48 — GrafiCode
– GrafiCode, Commented Oct 14, 2015 at 18:48

Vitor Rigoni · Accepted Answer · 2015-10-14 18:48:55Z

1

Remove the global $folder; from your function foo() and it shall work. Another alternative is adding the keyword global to your declaration:

$folder = "/test";

function foo(){
    require_once($_SERVER['DOCUMENT_ROOT'].$folder."/order/includes/db.php");
    ..do stuff

}

OR

global $folder = "/test";

function foo(){
global $folder;
require_once($_SERVER['DOCUMENT_ROOT'].$folder."/order/includes/db.php");
..do stuff

}

answered Oct 14, 2015 at 18:48

Vitor Rigoni

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1 Comment

WebDude0482 Over a year ago

global $folder = "/test" through me an error but calling global $folder after the far was fine. I also found that require_once was an issue in that it had been called before and therefore was not giving me the variables in the include file. Using just require fixed that issue

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