How can I write an invoke method with two parameters of differing variable types?
public void InsertStockPrice(double Value, string Company)
{
if (InvokeRequired)
{
Invoke(new Action<double>(InsertStockPrice), Value); // <- Not sure what to do here
}
else
{
//Do stuff
}
}
I suspect this is what Jimmy meant (as Control.Invoke wouldn't really know what to do with an Action<double, string>:
public void InsertStockPrice(double value, string company)
{
if (InvokeRequired)
{
MethodInvoker invoker = () => InsertStockPrice(value, company);
Invoke(invoker);
}
else
{
// Do stuff
}
}
If you're using C# 2:
public void InsertStockPrice(double value, string company)
{
if (InvokeRequired)
{
MethodInvoker invoker = delegate { InsertStockPrice(value, company); }
Invoke(invoker);
}
else
{
// Do stuff
}
}
Note that I've changed the case of your parameters to fit in with normal .NET conventions.
I think what you mean to be looking for is:
Action<Type1,Type2> yourAction = (type1Var, type2Var) =>
{
do stuff with type1Var and type2Var;
}
yourAction(var1, var2);
If this pattern is often repeated in code, you can make little helper method like this one
static class UiExtensions
{
public static void SafeInvoke(this Control control, MethodInvoker method)
{
if (control.InvokeRequired)
control.Invoke(method);
else
method();
}
}
this.SafeInvoke(() => { InsertStockPrices(value, company); });
