function overloading c++? [duplicate]

Question

when compiling this simple code,i get this error:

[Error] no matching function for call to 'Studente::Registra()'

#include<iostream>
using namespace std;
class Anagrafica{
public: 
    int codice;
    string cognome;
    string nome;
    void Mostra();
    void Registra();
private:
    bool registrato;
};
void Anagrafica::Registra()
{
    registrato=true;
}
void Anagrafica::Mostra()
{
    if(registrato){
        cout<<nome<<endl
            <<cognome<<endl
                <<codice;     
    }
    else
        cout<<"\nNon registrato \n";
}

class Studente : public Anagrafica{
    int anno;
    char sezione;
    bool promosso;
public: 
    void Registra(int, char);
    void Promuovi();
    void Controlla();
    void Mostra();

    Studente(){
        promosso = false;
        anno = 0;
    }
};

void Studente::Mostra()
{
    Anagrafica::Mostra();
    if (anno) cout<<anno<<" "<<sezione<<endl;
}

void Studente::Registra(int a, char s)
{
    anno = a;
    sezione = s;
}

void Studente::Promuovi()
{
    promosso = true;
}

void Studente::Controlla()
{
    if(promosso) cout<<"\nStudente promosso\n";
        else cout<<"\nStudente NON promosso\n";
}

int main(){
    Studente stud1;
    char risp,sez;
    int anno;
    cout<<"\nNome: ";
    cin>>stud1.nome;
    cout<<"\nCognome: ";
    cin>>stud1.cognome;
    cout<<"Codice: ";
    cin>>stud1.codice;
    cout<<"Anno Scolastico:  ";
    cin>>anno;
    cout<<"Sezione: ";
    cin>>sez;
    stud1.Registra(anno,sez);
    stud1.Registra();
    cout<<"Promosso? (s/n) ";
    cin>>risp;

    if (risp=='s') stud1.Promuovi();
    stud1.Mostra();
    stud1.Controlla();
    return 0; 

}

i dont understand the problem, shouldn't the function overloading should take care of the call for 'Registra()'?

Welcome to Stackoverflow. Please search for other questions related to your error first. Sadly there are upto 900 questions for this error message. Please consider editing your post to fix the code formatting. — try-catch-finally
– try-catch-finally, Commented Nov 14, 2015 at 11:08

tdao · Accepted Answer · 2015-11-14 11:04:17Z

1

No, because in child class Studente you declare Registra() with the same name in base class Anagrafica. This is not function overloading. The function in class Studente hides the function in class Anagrafica.

When you call stud1.Registra(); it only searches for void Registra(int, char); in child class which does not have matching prototype.

answered Nov 14, 2015 at 11:04

tdao

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Comments

Alan Stokes · Accepted Answer · 2015-11-14 11:18:33Z

1

You can fix this by adding using Anagrafica::Registra; in Studente.

That tells the compiler explicitly that you want the base class function to be considered when looking in Studente, rather than being hidden by your new function with the same name.

answered Nov 14, 2015 at 11:18

Alan Stokes

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