0
lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}


def average(numbers):

    total = sum(numbers)
    total = float(total)

    return total / len(numbers)

def get_average(student):
    homework = average(student['homework'])
    quizzes = average(student['quizzes'])
    tests = average(student['tests'])
    return sum(homework*  0.1 +\
               quizzes *  0.3 +\
               tests   *  0.6)           

I don't know what I'm doing wrong.

Forgot to put that I was getting: "error: 'float' is not iterable".

What I should get for example:

get_average(alice) : 91.15.

1
  • I don't know what you are doing wrong either! Post a problem statement and what output you should be getting vs what you are getting. Commented Nov 19, 2015 at 23:27

1 Answer 1

1

The sum built in function expects a sequence of numbers to sum as one argument. You are giving it only one number. In this case, you do not need to call the sum function at all:

 return homework*  0.1 +\
        quizzes *  0.3 +\
        tests   *  0.6  

Or, using sum properly:

 return sum([homework*  0.1,
            quizzes  *  0.3,
            tests    *  0.6])  
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2 Comments

that second one still isnt using sum properly, you need to put brackets around the arguments so its a single iterable rather than a separate parameters
But why do I need to use []? It worked with [], but I can't understand why do I need to use it. But now I see there's no need to use sum at all.

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