Check multiple conditions in `if` using for loop

Question

I have to check for multiple 'and' conditions in if Eg:

if (a[1]==b[1]) and (a[2]==b[2]) and (a[3]==b[3]) and (a[4]==b[4]):

can I do above using for loop in if, say something like

if (a[i]==b[i] for i in range(0,4)):

Above suggested won't work as it sets the condition as true even if one of them is true.

Here a and b are dictionaries. for i in range(0,4) could be substituted to for parameter in parameters — akipro
– akipro, Commented Nov 23, 2015 at 7:30

Remi Guan · Accepted Answer · 2015-11-23 07:39:54Z

7

Simply use all() here:

if all(a[i]==b[i] for i in range(1, 5)):

From the document:

Return True if all elements of the iterable are true (or if the iterable is empty).

And (a[i]==b[i] for i in range(1, 5)) return a generator(it's an iterable), then all() return True if all elements in that generator is True, else False. Like your code does.

edited Nov 23, 2015 at 7:39

answered Nov 23, 2015 at 7:30

Remi Guan

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1 Comment

Tim Over a year ago

@user3798653 if an answer solved your issue, consider accepting it

sundar nataraj · Accepted Answer · 2015-11-23 07:32:07Z

2

You can do

if all(a[i]==b[i] for i in range(1,5)):
    # logic here

Usage of all():

if all the elements in iterable are True returns True
if one lement is False it return False

eg: all([True,True]) --> True all([False,True])--> False

edited Nov 23, 2015 at 7:32

answered Nov 23, 2015 at 7:30

sundar nataraj

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1 Comment

sundar nataraj Over a year ago

@MartijnPieters Ahh,Sorry Forgot

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