Passing variable data to string date

Question

i want to pass variable in date function. it works while passing only one variable but if i pass two variable one for month and other for year then it does not work Please resolve

<?php
 $m = 'June';
 $y = '2011';
 echo $cutoff = date('m-d-Y', strtotime( $m . '01' . ' 2011'));
 echo '<br>';
 echo $nono = date('m-t-Y', strtotime( $m . '01' . $y)); 
?>

otezz · Accepted Answer · 2015-12-03 08:46:38Z

2

You might want to add space to your parameter

echo $nono = date('m-t-Y', strtotime( $m . ' 01 ' . $y));

answered Dec 3, 2015 at 8:46

otezz

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Nirnae · Accepted Answer · 2015-12-03 08:49:53Z

0

You have an error in your parameters, you need to add a space between day and year :

Not working

 echo $nono = date('m-t-Y', strtotime( $m . '01' . $y));

Working :

 echo $nono = date('m-t-Y', strtotime( $m . '01 ' . $y));

answered Dec 3, 2015 at 8:49

Nirnae

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Comments

Parth Chavda · Accepted Answer · 2015-12-03 08:51:02Z

0

change

echo $nono = date('m-t-Y', strtotime( $m . '01' . $y));

to

echo $nono = date('m-t-Y', strtotime( $m . ' 01 ' . $y));

answered Dec 3, 2015 at 8:51

Parth Chavda

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