Code in nested If statement not printing

Question

I have a problem and it is that my code isn't displaying after the nested statement.

After confirmation.lower == no, it asks the Wrong Info Input and then skips to the Else statement without executing what is in any of the if or elif statements.

confirmation = input("Confirm if information is correct ('yes' or 'no'):")

#confirms if deatils are incorrect
if confirmation.lower() == "no":
    wronginfo = input("Indicate Wrong Info:")
    if wronginfo.lower() == "First Name":

        NewInfo = input(wronginfo+":")
        FirstName = NewInfo
        details()


    elif wronginfo.lower() == "Last Name":

        NewInfo = input(wronginfo+":")
        LastName = NewInfo
        details()


    elif wronginfo.lower() == "Age":
        NewInfo = input(wronginfo+":")
        Age = NewInfo
        details()


   else:
    start = input("Type 'y' to start:")

Note: Details is a function that prints All info such as First Name and last name

Steven Summers · Accepted Answer · 2015-12-04 03:22:54Z

2

Your problem is that you have wronginfo.lower() == "Last Name": which contains upper case letters and will never be True.

Your options are. Change Last Name to last name

wronginfo.lower() == "last name"

If you would like to keep Last Name then you can use .title(). This will make the first letter of each word a capital and every other letter lower case, which matches what you're trying to compare.

wronginfo.title() == "Last Name"

answered Dec 4, 2015 at 3:22

Steven Summers

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Comments

user2683246 · Accepted Answer · 2015-12-03 22:14:02Z

1

You compare string with all characters in lower case to strings that consist upper case letters

answered Dec 3, 2015 at 22:14

user2683246

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Prune · Accepted Answer · 2015-12-03 22:15:06Z

1

This statement can never come up true:

elif wronginfo.lower() == "Last Name":

Your comparison string has upper-case characters; there is no lower-case string that can equal it. Perhaps try this:

elif wronginfo.lower() == "last name":

You will need the same treatment with "First Name" and "Age".

Now, if you like the way your current code reads, simply convert both to lower case like so:

elif wronginfo.lower() == "Last Name".lower():

You get the capitals for program maintenance at the cost of a small amount of CPU time. Since you're working at human typing speeds, that time is not likely to be a problem.

answered Dec 3, 2015 at 22:15

Prune

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Comments

Luke · Accepted Answer · 2015-12-03 22:14:55Z

0

wronginfo.lower() will never equal "First Name" because "First Name" has capital letters in it. Change to

if wronginfo.lower() == "first name":

answered Dec 3, 2015 at 22:14

Luke

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