Scala make List of strings from char array

Question

Here's what I'm trying to do:

val StringSpace = charList.reduce(_ + _ + _ + _ + " ")
val StringList = //Tokenize StringSpace with " "

but it returns missing parameter type within first line.

So how can someone actually join lists into half or quarter size in scala?

e.g: From

List ("a" , "b" , "c" , "d" , "e" , "f" , "g" , "h")

To:

List("abcd", "efgh")

dcastro · Accepted Answer · 2015-12-11 14:23:53Z

3

val l = List ("a" , "b" , "c" , "d" , "e" , "f" , "g" , "h")
l.grouped(4).map(_.mkString)

answered Dec 11, 2015 at 14:23

dcastro

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2 Comments

So how to make something like: List("abcd", "efgh") from "abcdefgh"?

Same thing. "abcdefgh".grouped(4).toList. A string behaves like a list of characters.

Odomontois · Accepted Answer · 2015-12-11 14:23:42Z

1

charList.grouped(4).map(_.mkString).toList

answered Dec 11, 2015 at 14:23

Odomontois

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