Groovy findAll in array of arrays

Question

I have the following array of arrays in groovy

def userList = [[name: user1, id:0, ip: 127.0.0.1], [name: user2, id:1, ip: 127.0.0.2], [name: user3, id:2, ip: 127.0.0.3]]

I am iterating over another list rows and I want to extract the entries from the above list based on index.

   rows.eachWithIndex { row, index ->
      groovy.lang.Closure idMatch = { it.id == index }
      def match = userList.findAll(idMatch)
      println(match)
   }

match is always returning empty.

The index value shows up correctly as 0,1,2 etc when I print it.

My guess is that id in your userList is not an Integer — tim_yates
– tim_yates, Commented Jan 6, 2016 at 16:00

dmahapatro · Accepted Answer · 2016-01-06 15:55:40Z

2

With Groovy 2.4 and above, one approach would be to use indices and collect() on rows instead of eachWithIndex:

def userList = [
    [name: 'user1', id:0, ip: '127.0.0.1'], 
    [name: 'user2', id:1, ip: '127.0.0.2'], 
    [name: 'user3', id:2, ip: '127.0.0.3']
]

def rows = ['foo', 'bar']

// Using indices
rows.indices.collect { index -> 
    userList.find { it.id == index } 
}

// Using indexed()    
rows.indexed().collect { index, item -> 
    userList.find { it.id == index } 
}

edited Jan 6, 2016 at 15:55

answered Jan 6, 2016 at 15:50

dmahapatro

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4 Comments

user2133404 Over a year ago

indexed() method or indices is not available it seems. rows is a list and I am using grails 2.4.4

dmahapatro Over a year ago

Makes sense, Grails 2.4.4 comes with Groovy 2.3.7.

dmahapatro Over a year ago

With what you have in question, it should print expected results. match does print results. @user2133404

user2133404 Over a year ago

Thanks, I had to cast the id to integer.

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