split xml file depending on record count in shell script

Question

I have temp.xml file with below contents,

   <records>
      <profile/>
      <profile/>
      <profile/>
      <profile/>
      .
      .
    </records>

I will pass the number of records,'n', as the input. I want the temp.xml file to be split into 'n' number of records. For eg., if I have 4 records in temp.xml and if I pass n value as 2, then 2 files has to be created with 2 records each.

The output file name can be anything. For eg., below is the sample output. where 4 records are split into 2 files with 2 records (profile). Records count should be consistent.

temp1.xml
<profile/>
<profile/>

temp2.xml
<profile/>
<profile/>

use awk, set RS='<profile' & based on n passed & NR value, change the output file name. — anishsane
– anishsane, Commented Jan 7, 2016 at 7:16
last file should contain remaining recods, for eg: temp.xml will have 13 records and split size is 2 then 6 file with 2 records and 7th file will contain 1 record. — sachin10
– sachin10, Commented Jan 7, 2016 at 7:17

sachin10 · Accepted Answer · 2016-01-07 08:03:44Z

2

i have splited the file using below command

split -l 3 -a 2 temp.xml remp.xml_

-a 2 :will be used to create file name like temp.xml_aa, temp.xml_ab

answered Jan 7, 2016 at 8:03

sachin10

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