PHP image dimension

Question

How to get width and height of an image?

I have $variable = 'http://site.com/image.png"

Want to get width of this image to $width and height to $height.

Like: $variable = 'http://site.com/image.png"

$width = '300'; // image width is 300px
$height = '500'; // height is 500px

Thanks.

anyway, here is a little magic: google.com/search?q=PHP+image+dimension — Your Common Sense
– Your Common Sense, Commented Aug 18, 2010 at 8:45
possible duplicate of quickest way to dynamically retrieve image dimensions — Pekka
– Pekka, Commented Aug 18, 2010 at 8:46
then it shouldn't be an url http://site.com/image.png but a filename. — Your Common Sense
– Your Common Sense, Commented Aug 18, 2010 at 9:16

Odi · Accepted Answer · 2013-08-12 21:35:21Z

2

$variable = 'http://site.com/image.png';
$image    = getimagesize($variable);
$width    = $image[0];
$height   = $image[1];
$type     = $image[2];

edited Aug 12, 2013 at 21:35

Odi

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answered Aug 18, 2010 at 8:53

Alex Pliutau

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Comments

Karasutengu · Accepted Answer · 2010-08-18 08:46:07Z

1

getimagesize function. Maybe it will help you.

answered Aug 18, 2010 at 8:46

Karasutengu

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2 Comments

Piskvor left the building Over a year ago

Caveat: the combination of remote FS and image functions can have subtle quirks, e.g. if the remote HTTP server is slow to respond, execution will hang until getimagesize() returns (which can be "until HTTP connection times out", which means tens of seconds).

symcbean Over a year ago

Certainly you want to cache the results of any image size check you do - if its at all possible.

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