How call method from new constructor in python?

Question

I am trying to call get_driver_path inside __new__ method, and I get this error when I try to run the full code:

TypeError: unbound method get_chrome_driver() must be called with
WebBrowserManager instance as first argument (got str instance instead

Here is the code:

def __new__(self, driver = 'firefox'):
    if not self._instance:
        self._instance = super(WebBrowserManager, self).__new__(self)
        self._profile.native_events_enabled = True
        self.data = {}
        self._system = platform.system()
        if self._local:
            if driver == 'firefox':
                self.browser = webdriver.Firefox(self._profile)
            elif driver == 'chrome':
                self.browser = self.get_chrome_driver(self._system, driver)
            elif driver == 'ie':
                assert self._system == 'Windows', 'Tests on Internet Explorer are only supported on Windows'
                self.browser = webdriver.Ie(self.get_driver_path(driver))
    return self._instance

def get_driver_path(self, driver):
    driver_name = ''
    if driver == 'ie':
        driver_name = 'IEDriverServer.exe'
    elif driver == 'chrome':
       driver_name = 'chromedriver.exe'
    driver_path = "selenium_drivers\\" + driver_name 
    os.environ["webdriver." + driver + ".driver"] = driver_path
    return driver_path

Martijn Pieters · Accepted Answer · 2016-02-01 21:23:18Z

2

Since you made it an instance method, you would need to call it on the instance you created in the __new__ method (which is static; e.g. not bound to an instance or a class):

self.browser = webdriver.Ie(self._instance.get_driver_path(driver))

You could make that method static or a class method instead, at which point you can use it via the first argument to __new__ (which is the class, not an instance; usually you don't use the name self but cls instead):

@staticmethod
def get_driver_path(driver):

Note that a staticmethod then doesn't take a self argument, but your get_driver_path() implementation doesn't use that anyway.

answered Feb 1, 2016 at 21:23

Martijn Pieters

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