String encoding - Swift

Question

I am using the following method to encode a string in objective - C:

+(NSString*)urlEncoded:(NSString*)string
{ return ((NSString *)CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes (NULL,(CFStringRef)string, NULL,(CFStringRef)@"! '=();@&+$%#",kCFStringEncodingUTF8 )));}

Is there any counterpart for this method in Swift 2.0 ? I have tried using many solutions present on stack, but none of them could solve my problem.

Nate Cook · Accepted Answer · 2016-02-05 06:48:08Z

2

You probably want to use stringByAddingPercentEncodingWithAllowedCharacters with NSCharacterSet's URL-component specific character sets:

let title = "NSURL / NSURLComponents"
let escapedTitle = title.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())

The idea behind those character sets is that they're probably more correct for the uses they describe than any finite set you have. That said, you could use the same method with a set you generate yourself:

let escapeSet = NSCharacterSet(charactersInString: "! '=();@&+$%#")
let string =  "sdfT&*w5e#sto([+peW7)%y9pqf])"
let escapedString = string.stringByAddingPercentEncodingWithAllowedCharacters(escapeSet.invertedSet)
// "sdfT%26*w5e%23sto%28[%2BpeW7%29%25y9pqf]%29"

edited Feb 5, 2016 at 6:48

answered Feb 5, 2016 at 2:37

Nate Cook

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3 Comments

Vamshi Krishna Over a year ago

Not working. My string is "sdfT&*w5e#sto([+peW7)%y9pqf])". I want to encode this.

Nate Cook Over a year ago

@VamshiKrishna: Updated!

Vamshi Krishna Over a year ago

It worked. But with a minor update. Replacing "! '=();@&+$%#" by "! '=()[];@&+$%#". Thanks

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