Is there any way to on Firebae to filter data in an array?
I have this model on my Firebase:
-KABIGeWnBMUKjLTcvp8
deviceToken:"7DE60240CB4B712F05A009F32358610C1327917E7E68409..."
favorites
0:"Masha"
1:"moksha"
name:"juan"
And the problem is that I can't find any method to get all "users" that contain a certain value on the "favorites" array field.
Nope, that's not an option See firebase equivalent to sql where in ().
Instead: invert your data structure to make this query possible:
items_by_favorites
"Masha"
"-KABIGeWnBMUKjLTcvp8"
"moksha"
"-KABIGeWnBMUKjLTcvp8"
Now you can look up the item keys for Masha with a simple read: ref.child('items_by_favorites/Masha') and then load each item:
ref.child('items_by_favorites/Masha').on('value', function(snapshot) {
snapshot.forEach(function(childSnapshot) {
var key = childSnapshot.key();
ref.child('items').child(key).once('value', function(itemSnapshot) {
console.log(itemSnapshot.val());
});
});
})
First of all your question is answered deep in the guide for retrieving data, which is where I got this answer. It's under complex queries, then range queries, should you want more info.
var ref = new Firebase("https://dinosaur-facts.firebaseio.com/dinosaurs");
ref.orderByChild("height").equalTo(25).on("child_added", function(snapshot) {
console.log(snapshot.key());
});
The basic idea is that you need to first order the reference by a common child value, and then call .equalTo() to end up with a query that yields what you want.
Also you can call order by child like
ref.orderByChild("height/sublevel")
To drill deeper in the tree.
FirebaseFirestore.instance.collection('your collection name').where('favorite', arrayContains: 'Masha').snapshot();
