How to convert JSON object into java jsonReader

Question

I have a JSON as below:-

{
    "products":
    {
        "productsApp15": {
            "code": "productsApp16",
            "name": "productsApp16",
            "attribute_set": "Apparel",
            "product_type": "product",
            "status": "active"
            }
    }
}

Now I need a function which can convert it like below automatically:-

 final JsonReader jsonReader = Json.createReader(new StringReader("{\n" +
                "    \"products\":\n" +
                "    {\n" +
                "        \"productsApp13\": {\n" +
                "            \"code\": \"productsApp13\",\n" +
                "            \"name\": \"productsApp13\",\n" +
                "            \"attribute_set\": \"Apparel\",\n" +
                "            \"product_type\": \"product\",\n" +
                "            \"status\": \"active\"\n" +
                "            }\n" +
                "    }\n" +
                "}"));

For that I tried to append/concatenate the string with /n but it was taken up as new line. I know it is right to but is there any way by which I can get that output automatically.

I tried something like below:-

        String sCurrentLine;
        StringBuilder sb = new StringBuilder("");
        br = new BufferedReader(new FileReader("./src/test/com/testdata/HTTPHelperTest.csv"));

    while ((sCurrentLine = br.readLine()) != null) {
        sb.append(sCurrentLine);
        sb.append("\n");
    }
    br.close();
    System.out.println("Value Json"+sb);

Any solution is appreicable.

Harshul Pandav · Accepted Answer · 2016-03-21 14:58:49Z

1

You need to add an escape character \ for \n

 while ((sCurrentLine = br.readLine()) != null) {
        sb.append(sCurrentLine);
        sb.append("\\n");
    }

answered Mar 21, 2016 at 14:58

Harshul Pandav

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2 Comments

Shubham Jain Over a year ago

Thanks .. Your answer have provide me lil solution of one part .. vote up for same.. but it is still not making string like above .. I also sb.append("+");

Harshul Pandav Over a year ago

Well, "+" exists in your second code sample exists since the string has been parted to separate lines for better visibility. You can use tabs \t and new line \n to make it look like the first code sample in your question.

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