Update item of json array

Question

I have a json array

[{
    "sku": "5221",
    "qty": 1,
    "price": 17.5,
    "desc": "5395 - Replenish Natural Hydrating Lotion 3.5oz"
}, {
    "sku": "11004",
    "qty": 1,
    "price": 30.95,
    "desc": "150 - Q-Plus 16oz"
}]

i am getting this array inside $item php variable and decoding that array

$jsonDecode = json_decode($items, true);
echo 'before' . PHP_EOL;
print_r($jsonDecode);

foreach ($jsonDecode as $key => $obj) {
    if ($obj->sku == '11004') {
        $jsonDecode[$key]['qty'] = '5';
    }
}
print_r($jsonDecode);

now i want if sku is 11004 then qty of that index would be 5 . but after using above code i got same array with same qty for that index.

how can i do so Please Help.

your json string doesn't seem to be valid. show the full json string — RomanPerekhrest
– RomanPerekhrest, Commented Apr 14, 2016 at 8:24
yes @ChetanAmeta i want to update qty of same json with 11004 sku and then want to save in DB. i am print json decoded array two time 1st before implementing foreach and 2nd after implementing foreach but getting same array without any change — Karan Adhikari
– Karan Adhikari, Commented Apr 14, 2016 at 8:36

mitkosoft · Accepted Answer · 2016-04-14 08:30:41Z

4

try below solution:

$json = '[{
    "sku": "5221",
    "qty": 1,
    "price": 17.5,
    "desc": "5395 - Replenish Natural Hydrating Lotion 3.5oz"
}, {
    "sku": "11004",
    "qty": 1,
    "price": 30.95,
    "desc": "150 - Q-Plus 16oz"
}]';

$array = json_decode($json, true);
//print_r($array);

foreach($array as &$a){
    if($a['sku'] == 11004){
        $a['qty'] = 5;
    }
}

echo json_encode($array);

output:

[{
    "sku": "5221",
    "qty": 1,
    "price": 17.5,
    "desc": "5395 - Replenish Natural Hydrating Lotion 3.5oz"
}, {
    "sku": "11004",
    "qty": 5,
    "price": 30.95,
    "desc": "150 - Q-Plus 16oz"
}]

edited Apr 14, 2016 at 8:30

mitkosoft

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answered Apr 14, 2016 at 8:28

Chetan Ameta

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5 Comments

Karan Adhikari Over a year ago

Tried but still getting same array without any qty change.

Chetan Ameta Over a year ago

have you used & with val in foreach loop .... working fine for me.. have a look at 3v4l.org/1IBIO

Karan Adhikari Over a year ago

Worked dude thanks , but can you please tell me why we are using & here?

Shri Suresh Over a year ago

@KaranAdhikari -> By default, function arguments are passed by value (so that if the value of the argument within the function is changed, it does not get changed outside of the function). To allow a function to modify its arguments, they must be passed by reference. To have an argument to a function always passed by reference, prepend an ampersand (&) to the argument name in the function definition. link

Karan Adhikari Over a year ago

Thank you @ShriSuresh for clarification i really appreciate this.

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