Url and title with php snippet

Question

I read several similar posts but I don't see my fault.

index.php looks like:

<head>
<title>Demo Title</title>
</head>
<body>
<?php 
    require_once "footer.php";
?>
</body>

footer.php looks like:

<?php
/*
 * _$ Rev. : 08 Sep 2010 14:52:26 $_
 * footer.php
 */

$host = $_SERVER['SERVER_NAME'];
$param = $_SERVER ['REQUEST_URI'];
$url = "http://".$host.$param;
echo $url;

$file = @ fopen($_SERVER[$url],"r") or die ("Can't open HTTP_REFERER.");
$text = fread($file,16384);
if (preg_match('/<title>(.*?)<\/title>/is',$text,$found)) {
        $title = $found[1];
} else {
        $title = " -- no title found -- ";
}
?>

A request for the URL http://127.0.0.1/test/index.php results in:

http://127.0.0.1/test/index.phpCan't open HTTP_REFERER.

or for http://127.0.0.1/test/

http://127.0.0.1/test/Can't open HTTP_REFERER.

Any hints appreciated.

Does this not cause a never ending loop for your server requests. because, your trying to request a file your spitting out so each fopen you make to index.php you cause it to fopen again and so on! this is a fail. this may explain your comment below of Server ran out of threads to serve requests — RobertPitt
– RobertPitt, Commented Sep 8, 2010 at 13:16

Spudley · Accepted Answer · 2010-09-08 13:12:33Z

$_SERVER is an array which contains a bunch of fields relating to the server config. It does not contain an element named "http://".$host.$param, so trying to open that as a filename will result in the fopen call failing, and thus going to the die() statement.

More likely what you wanted to do was just open the file called "http://".$host.$param. If that's what you want, then just drop the $_SERVER[] bit and it should work better.

Note that because it's a URL, you will need your PHP config to allow opening of remote files using fopen(). PHP isn't always configured this way by default as it can be a security risk. Your dev machine may also be configured differently to the system you will eventually deploy to. If you find you can't open a remote URL using fopen(), there are alternatives such as using CURL, but they're not quite as straightforward as a simple fopen() call.

Also, if you're reading the whole file, you may want to consider file_get_contents() rather than fopen() and fread(), as it replaces the whole thing into a single function call.

yousefcisco · Accepted Answer · 2010-09-08 13:04:41Z

1

try this:

$file = @ fopen($url,"r") or die ("Can't open HTTP_REFERER.");

answered Sep 8, 2010 at 13:04

yousefcisco

1272 silver badges13 bronze badges

4 Comments

vbd Over a year ago

$_SERVER[$url] is the first error. I replaced the line with your solution but the browser doesn't respond. error.log shows up nothing, until now.

vbd Over a year ago

error.log shows [Wed Sep 08 15:07:09 2010] [warn] Server ran out of threads to serve requests. Consider raising the ThreadsPerChild setting

yousefcisco Over a year ago

why are you using the full URL to open the file? if its on the same server can't you just use a local link (eg. "index.php" rather than "127.0.0.1/index.php")

yousefcisco Over a year ago

also why is there an @ before fopen? are you sure it's needed? tizag.com/phpT/fileopen.php

Gary Green · Accepted Answer · 2010-09-08 13:17:31Z

0

Try

<?php

$dom = new DOMDocument();

$host = $_SERVER['SERVER_NAME'];
$param = $_SERVER ['REQUEST_URI'];
$url = "http://".$host.$param;

echo 'getting title for page: "' . $url . '"';

$dom->loadHTML($url);

$dom->getElementsByTagName('title');

if ($dom->length)
{
    $title = $dom->item(0);
    echo $title;
}
else
{
    echo 'title tag not found';
}



?>

answered Sep 8, 2010 at 13:17

Gary Green

22.4k6 gold badges52 silver badges76 bronze badges

1 Comment

vbd Over a year ago

I replaced the footer.php with your script. The browser shows getting title for page: "127.0.0.1/test" but no title or the title tag not found message

RobertPitt · Accepted Answer · 2010-09-08 14:05:38Z

0

I can see your trying to track the referral's title

You need to use $_SERVER['HTTP_REFERER']; to get that

what you want to do is something like this

    $referrer = (!empty($_SERVER['HTTP_REFERER']) && !substr($_SERVER['SERVER_NAME']) ? $_SERVER['HTTP_REFERER'] : false);

    if($referrer)
    {
        try
        {
            if(false !== ($resource = fopen($referrer,"r")))
            {
                $contents = '';
                while($contents .= fread($resource,128))
                {}

                if(preg_match('/<title>(.*?)<\/title>/is',$contents,$found))
                {
                     echo 'Referrer: ' $found[1];
                }
            }
        }catch(Exception $e){}
    }

answered Sep 8, 2010 at 14:05

RobertPitt

57.3k21 gold badges117 silver badges161 bronze badges

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