I'd like to know how to parse (or split) and element of a list?
I have a list of lists (of string) such as:
resultList = [['TWP-883 PASS'], ['TWP-1080 PASS'], ['TWP-1081 PASS']]
where:
resultList[0] = ['TWP-883 PASS']
resultList[1] = ['TWP-1080 PASS']
essentially, I need a variable for the two entries in each element of the list. For example:
issueId = 'TWP-883'
status = 'PASS'
What would allow for iterating through this list and parsing such as above?
Well that's as simple as:
# You can also assign as you iterate as suggested in the comments.
for issue, status in resultList:
print issue, status
This outputs
TWP-883 PASS
TWP-1080 PASS
TWP-1081 PASS
TWP-1082 PASS
TWP-884 FAIL
TWP-885 PASS
Here's another example:
>>> x = [1, 2] # or (1, 2), or '12' works with collections
>>> y, z = x
>>> y
1
>>> z
2
>>>
Incidentally, in Python 3.x, you can also do:
In [1]: x = [1, 2, 3, 4]
In [2]: y, z, *rest = x
In [3]: y
Out[3]: 1
In [4]: z
Out[4]: 2
In [5]: rest
Out[5]: [3, 4]
for issueId,status in resultList (+1 all the same)
Note: I changed this answer to reflect an edit of the question. Specifically, I added a split() to separate the strings in the nested lists into two strings (issueId and status).
I would use list and dictionary comprehensions to turn your list of lists into a list of dictionaries with the keys issueId and status:
resultList = [['TWP-883 PASS'], ['TWP-1080 PASS'], ['TWP-1081 PASS']]
result_dicts = [{("issueId","status")[x[0]]:x[1] for x in enumerate(lst[0].split())} for lst in resultList]
Lookups can now be done in this way:
>>> result_dicts[0]["status"]
'PASS'
>>> result_dicts[0]["issueId"]
'TWP-883'
>>> result_dicts[1]
{'status': 'PASS', 'issueId': 'TWP-1080'}
>>>
To declare variables for each value in each dictionary in the list and print them, use the code below:
for entry in result_dicts:
issueId = entry["issueId"]
status = entry["status"]
print("The status of {0: <10} is {1}".format(issueId, status))
Output:
The status of TWP-883 is PASS
The status of TWP-1080 is PASS
The status of TWP-1081 is PASS
You just need a simple for loop that exploits Python's tuple unpacking machinery.
for issueId, status in resultList:
# Do stuff with issueId and status
If you wish to do more transformations later, use a genexp,
g = (func(issueid, status) for issueid, status in resultList) # func returns non-None objects
If you just want to consume the iterable,
for issueid, status in resultList:
# print(issueid, status)
# whatever
You can get the list of the strings by
issueId = [y for x in resultList for (i,y) in enumerate(x.split()) if(i%2==0)]
status = [y for x in resultList for (i,y) in enumerate(x.split()) if(i%2==1)]
to go through every issueID and corrosponding status you can use
for id,st in zip(issueId,status):
print(id, " : ", st)
