SyntaxException in python method. Unsure why

Question

Can anyone explain why I get the following syntax error when running the setup.py install:

Exception

SyntaxError: ('invalid syntax', ('build/bdist.linux-x86_64/egg/cardstream/payment.py', 46, 15, '            for key, value in parse_qs(query).items()\n'))

Code

 @classmethod
 def decode(this, query):

      """Decode a request/response from the given query string.
      """

      return {
          key: value if len(value) > 1 else value[0]
              for key, value in parse_qs(query).items()
      }

The line it refers to is the for. I'm familiar with Python, but not so much that I can figure out why it's moaning.

Edit For completeness, here is the exception when the script is run manually:

[...pythonsdk]$ python test/test_gateway.py
Traceback (most recent call last):
  File "test/test_gateway.py", line 4, in <module>
    from REMOVED.payment import Gateway
  File "/usr/lib/python2.6/site-packages/REMOVED-0.0.1-py2.6.egg/REMOVED/payment.py", line 46
    for key, value in parse_qs(query).items()
      ^
SyntaxError: invalid syntax

Oh, maybe. Running on a box that probably hasn't been updated for some time. I'll check. Thanks. — NoGall
– NoGall, Commented Jun 2, 2016 at 5:29
Yes, from those paths it looks like you have Python 2.6. Dictionary comprehensions were added in 2.7. — BrenBarn
– BrenBarn, Commented Jun 2, 2016 at 5:44
Unfortunately the live box only has 2.6, but I was able to confirm this was the case by installing 2.7.x on a windows box and running. Thanks for your help — NoGall
– NoGall, Commented Jun 2, 2016 at 5:48

Ignacio Vazquez-Abrams · Accepted Answer · 2016-06-02 06:48:43Z

1

Just convert the dict comprehension to the equivalent dict() constructor call:

return dict((
          (key, value if len(value) > 1 else value[0])
              for key, value in parse_qs(query).items()
      ))

answered Jun 2, 2016 at 6:48

Ignacio Vazquez-Abrams

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Comments

Dmitry Tokarev · Accepted Answer · 2016-06-03 05:03:19Z

0

It doesn't like you splitting your dictionary comprehension on separate lines.

Just put it on a single line:

return {
    key: value if len(value) > 1 else value[0] for key, value in parse_qs(query).items()
}

or if you absolutely have to split use line continuation character \

return {
    key: value if len(value) > 1 else value[0] \
        for key, value in parse_qs(query).items()
}

edited Jun 3, 2016 at 5:03

answered Jun 2, 2016 at 6:39

Dmitry Tokarev

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1 Comment

NoGall Over a year ago

This has been solved by using Python 2.7.x rather than the 2.6.6 version on the live box. But thanks for your time :)

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