(laravel) Query builder using model of variable name

Question

I'm trying to insert into a table using its laravel model class, but I need to be able to insert into the table indicated by a variable. How can this be done? I tried the vanilla PHP moethod and the laravel facade method but both gave me errors:

$modelName = "model";

# this works no problem:
$model = new model();

# this blows up:
$model = new $modelName();

# this blows up:
$model::create($request->all());

the error given by laravel:

FatalThrowableError in Controller.php line 44:
Class 'model' not found

@Ohgodwhy Thanks for catching that. I updated the question, but the error didn't change. — Skeets
– Skeets, Commented Jun 22, 2016 at 0:50

Doom5 · Accepted Answer · 2016-06-22 01:08:23Z

6

You must put the fully qualified class name:

One must use the fully qualified name (class name with namespace prefix).

$modelName = "App\\User"; // assuming User is located in the App namespace
$model = new $modelName();

You can learn more about it here.

edited Jun 22, 2016 at 1:08

answered Jun 22, 2016 at 0:54

Doom5

8589 silver badges18 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Skeets Over a year ago

Thanks! that worked. I guess including the class path always has to be explicit in this case even when the class has been included?

Skeets Over a year ago

also, why is it a backslash here instead of a foward slash?

Doom5 Over a year ago

I've edited my answer to include the link to related part of the PHP documentation. 1) Yes, it seems so. 2) It is the one used by PHP, right? :)

Collectives™ on Stack Overflow

(laravel) Query builder using model of variable name

1 Answer 1

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related