php regex capturing parantheses

Question

I can't capture what i want with capturing parantheses... I'm searching in /hodsakers/marsh-zwartArray/d and i want to capture marsh-zwartArray but sometimes the last / is not present in what i'm searching. I search and try many things =/ like :

(marshall[\s\S]*)\/

it work but if the last backslash is not present it doesn't. I also try

(marsh[\s\S]*)(\/)?

in this case that's the opposite, it work without the last backslash but not anymore if there is one, it will get all the string and capture nothing =/ So i don't know how i can capture in both cases =/ Thanks for your help

Do you want to match with all occurrences of 'marsh*' ? For example for the following case is going to match for twice if you example above /hodsakers/marsh-zwartArray/whatevermarsh — Ezequiel De Simone
– Ezequiel De Simone, Commented Jun 26, 2017 at 14:08

Jonathan Kuhn · Accepted Answer · 2016-07-19 22:34:41Z

2

You may use a [^\/]* negated character class to match 0+ chars other than /:

/marsh[^\/]*/

See the regex demo

edited Jul 19, 2016 at 22:34

Jonathan Kuhn

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answered Jul 19, 2016 at 22:26

Wiktor Stribiżew

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1 Comment

renan Over a year ago

Thanks a lot, it was the negated character, problem is solved

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