100

I am looking to do some error checking for my command line arguments

public static void main(String[] args)
{
    if(args[0] == null)
    {
        System.out.println("Proper Usage is: java program filename");
        System.exit(0);
    }
}

However, this returns an array out of bounds exception, which makes sense. I am just looking for the proper usage.

6 Answers 6

179

The arguments can never be null. They just won't exist.

In other words, what you need to do is check the length of your arguments.

public static void main(String[] args) {
  // Check how many arguments were passed in
  if (args.length == 0) {
    System.out.println("Proper Usage is: java program filename");
    System.exit(0);
  }
}
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Comments

21

@jjnguy's answer is correct in most circumstances. You won't ever see a null String in the argument array (or a null array) if main is called by running the application is run from the command line in the normal way.

However, if some other part of the application calls a main method, it is conceivable that it might pass a null argument or null argument array.

However(2), this is clearly a highly unusual use-case, and it is an egregious violation of the implied contract for a main entry-point method. Therefore, I don't think you should bother checking for null argument values in main. In the unlikely event that they do occur, it is acceptable for the calling code to get a NullPointerException. After all, it is a bug in the caller to violate the contract.

Comments

12

To expand upon this point:

It is possible that the args variable itself will be null, but not via normal execution. Normal execution will use java.exe as the entry point from the command line. However, I have seen some programs that use compiled C++ code with JNI to use the jvm.dll, bypassing the java.exe entirely. In this case, it is possible to pass NULL to the main method, in which case args will be null.

I recommend always checking if ((args == null) || (args.length == 0)), or if ((args != null) && (args.length > 0)) depending on your need.

Comments

1

You should check for (args == null || args.length == 0). Although the null check isn't really needed, it is a good practice.

1 Comment

Unnecessary checks are NOT good practice. The null check is unnecessary, but you are correct that the length check is necessary,
0

if i want to check if any speicfic position of command line arguement is passed or not then how to check? like for example in some scenarios 2 command line args will be passed and in some only one will be passed then how do it check wheather the specfic commnad line is passed or not?

public class check {

public static void main(String[] args) {
if(args[0].length()!=0)
{
System.out.println("entered first if");
}
if(args[0].length()!=0 && args[1].length()!=0)
{
System.out.println("entered second if");
}
}
}

So in the above code if args[1] is not passed then i get java.lang.ArrayIndexOutOfBoundsException:

so how do i tackle this where i can check if second arguement is passed or not and if passed then enter it. need assistance asap.

1 Comment

Please make this a question. Since it does not answer the question, it doesn't belong here. By asking a question instead, you have a much better chance of getting an answer.
-10

If you don't pass any argument then even in that case args gets initialized but without any item/element. Try the following one, you will get the same effect:

 
public static void main(String[] args) throws InterruptedException {
        String [] dummy= new String [] {};
        if(dummy[0] == null)
        {
            System.out.println("Proper Usage is: java program filename");
            System.exit(0);
        }

    }

10 Comments

This is totally incorrect. If an application is launched with no command line arguments, the main method will be called with an args array whose length is zero.
@Stephen An array without any element inside, has zero length. Then what's wrong about my answer?
@Puspendu - what is wrong is that dummy[0] throws an array index out of bounds exception!! Ditto if you change the program (back) to testing args[0] and run it with no arguments.
OK - I understand now. It would have helped if you hadn't mistyped your first sentence. As written it is unintelligible. I note that you quietly corrected it in your last comment. Sneaky.
"I have not given any solution rather I tried to describe the issue". Then don't post an answer. Post a comment.
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