How to split string with defining multiple regular expression in clojure?

Question

I'm new in clojure programming. I'm learning about splitting a string by defining regular expressions. I'm learning from here https://clojuredocs.org/clojure.string/split

I want to split a string by defining two regular expressions. For example:

=> (require '[clojure.string :as str])

=> (str/split "Hello world! Have a nice day" #" ")
;; ["Hello" "world!" "Have" "a" "nice" "day"]

=> (str/split "Hello world!\nHave a nice day" #"\n")
;; ["Hello world!" "Have a nice day"]

This is cool. Now I'd like to split a string on every space & newline.

If the input is "Hello world!\nHave a nice day", The output should be ["Hello" "world!" "Have" "a" "nice" "day"]

can anyone suggest me, How can I do this? Thanks.

leetwinski · Accepted Answer · 2016-08-08 07:46:27Z

5

i would recommend you to use #"\s+" as the splitting regex, because \s symbol class includes all the whitespace characters (as of java regex they are [ \t\n\x0B\f\r]. (https://docs.oracle.com/javase/tutorial/essential/regex/pre_char_classes.html).

user> (clojure.string/split "Hello world! Have  a nice   day\naaa bbb" #"\s+")
["Hello" "world!" "Have" "a" "nice" "day" "aaa" "bbb"]

answered Aug 8, 2016 at 7:46

leetwinski

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1 Comment

Amit Over a year ago

Thanks a lot. I got my answer.

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