I want to know how to copy elements of one array returned by a function into another array in a different function.
Eg:
func PossibleMoves()[8] int{
/* calculations*/
return Posmoves[]
}
func traversal(){
var currentarray [8] int
copy(Posmoves,currentarray)
}
This shows an error saying undefined Posmoves, How should I correct it...
Copy function is used with two slices as arguments (1 -> dst, 2 -> src), then, you must use two slices or convert your [8]int arrays to slices, you could do it using [:] operator. This operator will return a slice that will have a reference to [8]int array.
Posmoves is undefined because you didn't define in any place. Then, you could create a global variable:
var Posmoves [8]int
func main() {
PossibleMoves()
traversal()
fmt.Println(Posmoves)
}
func PossibleMoves() [8]int {
/* calculations*/
return Posmoves
}
func traversal() {
var currentarray [8]int
copy(Posmoves[:], currentarray[:])
}
It returns [0 0 0 0 0 0 0 0] because both arrays are initialized to zero value (default value).
You could execute trasversal() too and this will get Posmoval array from PossibleMoves(). So:
func main() {
traversal()
}
func PossibleMoves() [8]int {
/* calculations*/
var Posmoves [8]int
return Posmoves
}
func traversal() {
var currentarray [8]int
Posmoves := PossibleMoves()
copy(Posmoves[:], currentarray[:])
fmt.Println(currentarray)
}
The output will be again: [0 0 0 0 0 0 0 0]
I hope it helps you! :-)
strs[0] = currentSource. And currentSource is initialized to zero (""). When you execute IsValid(currentSource), you try to access to 0 and 1 position of string b (currentSource) (b[0] and b[1]), but length of currentSource or b is 0. Try this play.golang.org/p/XMbXWDLY9mSlices are descriptors (headers pointing to a backing array), not like arrays which are values. An array value means all its elements.
So in order to copy all the elements from one array into another, you don't need any "special" copy function, you just need to assign the array value.
Seriously, this is all what you need:
var currentarray [8]int = PossibleMoves()
Or you can use short variable declaration and then it's just
currentarray := PossibleMoves()
See this simple example:
var a [8]int
var b = [8]int{1, 2, 3, 4, 5, 6, 7, 8}
fmt.Println(a, b)
a = b
fmt.Println(a, b)
a[0] = 9
fmt.Println(a, b)
Output (try it on the Go Playground):
[0 0 0 0 0 0 0 0] [1 2 3 4 5 6 7 8]
[1 2 3 4 5 6 7 8] [1 2 3 4 5 6 7 8]
[9 2 3 4 5 6 7 8] [1 2 3 4 5 6 7 8]
As you can see, after the assignment (a = b), the a array contains the same elements as the b array.
And the 2 arrays are distinct / independent: modifying an element of a does not modify the array b. We modified a[0] = 9, b[0] still remains 1.
