Way to handle string in Java

Question

I would like to remove all digits that come at the start of a string. I would just like to remove the digits at the start, not at the end or the middle.

Example: "123string67" to "string67"

Is there some function or regex I can use to easily do this?

"maybe there is an easy regex command". There is. What did you try? Or are you asking us to write the regex for you, without doing any research on your own? Down-voted for lack of research. — Andreas
– Andreas, Commented Sep 12, 2016 at 18:05

vsminkov · Accepted Answer · 2016-09-12 18:50:53Z

1

You can use group capture and ^\d*(.*) regex

Pattern pattern = java.util.regex.Pattern.compile("^\\d*(.*)")
Matcher matcher = pattern.matcher("123string67")
if (matcher.matches()) {
    String truncated = matcher.group(); //string67
}

Here is a regex explained

^    - start of string
\d*  - zero or more digit
 (   - group capture start
  .* - any symbol
 )   - group capture end

answered Sep 12, 2016 at 18:50

vsminkov

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PEF · Accepted Answer · 2016-09-12 19:03:18Z

0

Here's a hint (without regex): (*you still need to consider the case where the string is empty or contains only digits)

int i=0;
while(isDigit(str.charAt(i))) {
    str.deleteCharAt(i);
}

answered Sep 12, 2016 at 19:03

PEF

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Barkın Kandıran · Accepted Answer · 2016-09-12 19:08:52Z

0

You can use for ( i.. To i.string.lenght..) and control with ASCII number and delete digit number so you can replaced your string as you want i hope this helpful for you

answered Sep 12, 2016 at 19:08

Barkın Kandıran

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