Variable undefined error in laravel blade view

Question

Hey as i am passing a blade view which is having it own controller also i am including it into the view which does not have its own controller. it gives me an undefined variable error can any one help me how to it.

I have a view which does not have any controller only have Route like this Route::get('index', function () { return view('index'); }); in this view i am passing another view which having its own controller and also having some data from an array. but after using this view inside the view i get undefined variable error.

i am having a view which is does not have any controller only have Route like this Route::get('index', function () { return view('index'); }); in this view iam passing another view which is having its own controller and also having some data from an array. but after using this view inside the view i get undefined variable error — Priyank lohan
– Priyank lohan, Commented Sep 30, 2016 at 10:29

Community · Accepted Answer · 2020-11-17 20:07:01Z

27

Two steps :

Declare & transfer $variable to View from Controller function.

 public function index()
 {
  return view("index", [ "variable" => $variable ]);
 }

Indicate where transferred $variable from Controller appear in view.blade.php.
```
 {{ $variable }}
```

If you do not make sure, $variable is transferred or not

{{ isset($variable) ? $variable : '' }}

edited Nov 17, 2020 at 20:07

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answered Jan 11, 2017 at 7:35

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Comments

Community · Accepted Answer · 2020-10-19 07:32:49Z

4

If this helps anyone, I was completely ignorant to the fact that my route was not hooked with the corresponding controller function and was returning the view directly instead, thereby causing this issue. Spent a good half hour banging my head till I realized the blunder.

Edit

Here again to highlight another blunder. Make sure you're passing your array correctly. I was doing ['key', 'value] instead of ['key' => 'value'] and getting this problem.

edited Oct 19, 2020 at 7:32

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answered Sep 21, 2020 at 6:44

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Comments

AddWeb Solution Pvt Ltd · Accepted Answer · 2016-09-30 14:41:01Z

0

You can try this:

 public function indexYourViews()
  { 
    $test = "Test Views";
    $secondViews = view('second',compact('test'));

     return view('firstview',compact('secondViews'));
   }

and after declare {{$secondViews}} in your main view file(firstview).

Hope this helps you.

answered Sep 30, 2016 at 14:41

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renov8 · Accepted Answer · 2016-10-03 16:49:35Z

-1

public function returnTwoViews() {
    $variable = 'foo bar';
    $innerView = view('inner.view', ['variable' => $variable]);

    return view('wrapper.view, ['innerView' => $innerView]);
}

This may be what you are looking for?

... inside your wrapper.view template:

{!! $innerView !!}

EDIT: to answer the question in the comment: In order to fetch each line you for do this inside your $innerView view:

@foreach($variable as $item)
    {{ $item }}
@endforeach

... and in the wrapper view it will still be {!! $innerView !!}

edited Oct 3, 2016 at 16:49

answered Sep 30, 2016 at 10:30

renov8

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2 Comments

Priyank lohan Over a year ago

thanks it works greatly...what if i have a array of $variable. then how would i fetch the in my wrapper view.

renov8 Over a year ago

I have edited the original response because I need to include some more code for this case.

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