Save each line of echo output as variable BASH

Question

I'm working to create a simple script where I can save each line as a variable for later use. However it didn't go well. Can anybody help me please.

read -p  "Enter the number of user and press [ENTER]:" num
   for ((i=1; i<=$num; i++)); do
           var$i="|-> Line $i"
           echo "var$i"

   done

I'm trying to obtain the output that looks like this

|-> Line 1
|-> Line 2
|-> Line 3
|-> Line 4

FatalError · Accepted Answer · 2016-10-12 01:12:32Z

3

You're not too far off. Just use an array:

read -p  "Enter the number of user and press [ENTER]:" num
for ((i=0; i<$num; i++)); do
    var[$i]="|-> Line $((i+1))"
    echo "${var[i]}"
done

for line in "${var[@]}"
do
    echo "Saved line: $line"
done

where the latter gives an example how to retrieve it later. Also, arrays are zero-indexed and I've adjusted it accordingly.

answered Oct 12, 2016 at 1:12

FatalError

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3 Comments

K.U Over a year ago

This works perfectly. Thanks a lot ! So what you have done is put them into an array ?

Dai Kaixian Over a year ago

Yeah,your answer do it better.

FatalError Over a year ago

Yes, this puts them in an array. It also relies on the fact that an undefined variable (when used as an array) acts identically to an empty array. But you could also say var=() above to be more explicit and to clear anything that might have previously been defined in var.

Dai Kaixian · Accepted Answer · 2016-10-12 01:15:09Z

0

Can this meet your requirement?

read -p  "Enter the number of user and press [ENTER]:" num
   for ((i=1; i<=$num; i++)); do
       var_j="|-> Line $i"
       echo $var_j

   done

answered Oct 12, 2016 at 1:15

Dai Kaixian

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