how to create a php ternary expression containing only if statement

Question

How can I create a php ternary expression containing just if statement without the else part? This is what I tried :

$vn = condition ? expression1 ;

And this is what I'm trying to achieve

if(condition) {
    $vn = expression1;
}

to

$vn = condition ? expression1 ;

Bart Friederichs · Accepted Answer · 2016-10-12 19:45:15Z

3

You could use the same variable in the else part:

$vn = condition ? expression1 : $vn ;

Note this creates a notice if $vn was not used before.

answered Oct 12, 2016 at 19:45

Bart Friederichs

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2 Comments

You could use @$vn in the else part to prevent the notice.

@Barmar yes. But in fact you should initialise $vn first. Suppressing notices, warnings and errors is never a good idea.

The One and Only ChemistryBlob · Accepted Answer · 2016-10-12 19:53:44Z

1

If you are using PHP 7, you may want to consider the Null Coalescing Operator.

In certain cases, the syntax is similar to what you seem to be looking for:

$email = $_POST['email'] ?? 'none';

// is the same as:
$email = isset($_POST['email']) ? $_POST['email'] : 'none';

answered Oct 12, 2016 at 19:53

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JOUM · Accepted Answer · 2016-10-12 19:55:03Z

1

(condition) AND ($vn = expression1);

works too.

And only as info:

$v = condition?:expression1

is also possible, here the condition (in case) is parsed to $v

answered Oct 12, 2016 at 19:55

JOUM

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