Can i please know how the data from a file can be split into two separate lists. For example, file contains data as 1,2,3,4;5,6,7
my code:
for num in open('filename','r'):
list1 = num.strip(';').split()
Here , i want a new list before semi colon (i.e) [1,2,3,4] and new list after semi colon (i.e) [5,6,7]
If you are certain that your file only contains 2 lists, you can use a list comprehension:
l1, l2 = [sub.split(',') for sub in data.split(';')]
# l1 = ['1', '2', '3', '4']
# l2 = ['5', '6', '7']
More generally,
lists = [sub.split(',') for sub in data.split(';')]
# lists[0] = ['1', '2', '3', '4']
# lists[1] = ['5', '6', '7']
If integers are needed, you can use a second list comprehension:
lists = [[int(item) for item in sub.split(',')] for sub in data.split(';')]
To get the final list you need to split on "," as well (and probably map() the result to int()):
with open("filename") as f:
for line in f:
list1, list2 = [x.split(",") for x in line.rstrip().split(";")]
Depending on the size of your file, you could simply read the whole file into a string at once and then first split by semicolon, then by comma:
with open('filename', 'r') as f: #open file
s = f.read() #read entire contents into string
lists = s.split(';') #split separate lists by semicolon delimiters
for l in lists: #for each list
l = [int(x) for x in l.split(',')] #separate the string by commas and convert to integers
list1 = num.split(';')[0].split(',')list2 = num.split(';')[1].split(',')