Error in Swift JSON when receiving 'json_encode' from PHP script. Works fine without it

Question

I have a Swift function for a button that when pressed writes some details into a database via PHP:

 @IBAction func createCommunityButtonTapped(_ sender: AnyObject) {

    let communityName = communityNameTextField.text;
    if (communityName!.isEmpty){
        displayMyAlertMessage(userMessage: "You must name your Community");

        return;
    }else{

        func generateRandomStringWithLength(length: Int) -> String {

            var randomString = ""
            let letters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"

            for _ in 1...length {
                let randomIndex  = Int(arc4random_uniform(UInt32(letters.characters.count)))
                let a = letters.index(letters.startIndex, offsetBy: randomIndex)
                randomString +=  String(letters[a])
            }

            return randomString
        }

        let communityCode = generateRandomStringWithLength(length: 6)
        passwordTextField.text = communityCode

        let myUrl = URL(string: "http://www.quasisquest.uk/KeepScore/createCommunity.php?");

        var request = URLRequest(url:myUrl!);
        request.httpMethod = "POST";

        let postString = "communityname=\(communityName!)&code=\(communityCode)&email=\(myEmail!)";

        request.httpBody = postString.data(using: String.Encoding.utf8);

        let task = URLSession.shared.dataTask(with: request) { (data, response, error) in
        if (try! JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]) != nil {
            }
        } 

        task.resume()

    }

}

The function works great apart from whenever I add this echo jsonline into the PHP script:

if($newresult)
{
    $returnValue["status"] = "Success";
    $returnValue["message"] = "Community is registered";
    echo json_encode($returnValue);
    return;
}

Then I get an error Thread 8: EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP, subside = 0x0) on this line:

if (try! JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]) != nil { }

And in the debug area the following details

data Data? some response URLResponse? 0x0000618000223500 error Error? nil none

I think I'm missing a line, or need to set a variable to the JSONSerialization instead of 'try!' but I'm very unsure what.

Kinshuk Lahiri · Accepted Answer · 2016-10-20 09:05:55Z

2

You are returning null. Try this

if($newresult)
{
 $returnValue["status"] = "Success";
 $returnValue["message"] = "Community is registered";
 return json_encode($returnValue);
}

edited Oct 20, 2016 at 9:05

answered Oct 20, 2016 at 8:44

Kinshuk Lahiri

1,50010 silver badges24 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Error in Swift JSON when receiving 'json_encode' from PHP script. Works fine without it

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related