Fatal error: Can't use function return value in write context on line 50

Question

I am doing sharing form and I can´t find out the problem. What am I doing wrong?

<?php 
        if ($hlaska)
            echo('<p>' . htmlspecialchars($hlaska) . '</p>');

        $vasemail = (isset($_POST['vasemail'])) ? $_POST['vasemail'] : '';
        $email = (isset($_POST['email'])) ? $_POST['email'] : '';
        $predmet = (isset($_POST('predmet')) ? $_POST['predmet'] : '';
        $zprava = (isset($_POST['zprava'])) ? $_POST['zprava'] : '';
?>

This is code about line 50. Line 50 is starting with $predmet

If I comment or delete all code contenting something with $predmet it works as it should. $predmet is in English $subject FYI.

now u have 2 solutions given below, test it

devpro
– devpro

2016-10-28 10:47:35 +00:00
Commented Oct 28, 2016 at 10:47 — devpro
– devpro, Commented Oct 28, 2016 at 10:47

devpro · Accepted Answer · 2016-10-28 10:40:12Z

5

Just because of this $_POST('predmet')

This should be:

$predmet = (isset($_POST['predmet'])) ? $_POST['predmet'] : '';

You are getting the Fatal Error because this $_POST('predmet') consider here as a method which is wrong this is Super Global.

edited Oct 28, 2016 at 10:40

answered Oct 28, 2016 at 10:28

devpro

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4 Comments

Nana Partykar Over a year ago

Waah Bhai. Umda

devpro Over a year ago

@NanaPartykar: :)

pandik70 Over a year ago

Thank you, didn´t realise it.

devpro Over a year ago

@pandik70: glad to help u

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