How continue execute program after assertion in python?

Question

I am learning Exception in python and i have some doubt:

Can we use any name as error in raise?

like i have read when you use raise you have to define error type so can't i use any stringname as Error? like SkienaError or i have to keep in mind all the error types and have to use only those Error type names ?

    a=int(input())
if a!=10:
    raise SkienaError
else:
    print(a,"pp")

Second doubt is suppose i want user should input int but he input string so an assert pop up but i want program should continue without terminate and again ask for input until user give int type input , I don't want to use while loop here i want to know if it is possible with raise or assert in python ? like:

a=int(input())
assert type(a)==int
print(a,"hello")

So if user give str type input then is it possible program keep giving error and asking new input until input type is int.

Jordan McQueen · Accepted Answer · 2016-10-29 23:07:34Z

10

In order to make your own exception, you'll have to create it.

e.g.

class MyAppLookupError(LookupError):
'''raise this when there's a lookup error for my app'''

To continue execution after a thrown Exception, do it like this:

a = 5
try:
    assert a == 5
except AssertionError as e:
    print(e)

A try block will attempt to execute a block of code. If an exception occurs, it will execute the except block.

answered Oct 29, 2016 at 23:07

Jordan McQueen

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8 Comments

Eleutetio Over a year ago

i tried what you said but failed check out what i am trying to do : paste.ofcode.org/brZxC42zRerVbmwSRpkrv4

Jordan McQueen Over a year ago

except error is a syntax error. you want except AssertionError

Eleutetio Over a year ago

i can't define anyname ? i have to use specially "AssertionError" as keyword ??

Jordan McQueen Over a year ago

assert is a special keyword that raises an Exception of subctype AssertionError. You can write except Exception or except AssertionError. If you want to make your own, you'll have to write an Exception class for it.

Eleutetio Over a year ago

ok sure i tried again what you said but its not asking again for int if i am giving str type input : paste.ofcode.org/6SD7uwX6FNrvgppHxF5vEW

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Oleg Melnikov · Accepted Answer · 2021-01-22 04:34:56Z

0

This might also work for your situation. The function Assert() prints a message sTxt in red color, if the Boolean input bCond is False and interpreter continues execution:

RED, END = '\033[91m', '\033[0m'
printRed = lambda sTxt: print(RED + sTxt + END)
Assert = lambda bCond=False, sTxt='': printRed(sTxt) if not bCond else None

answered Jan 22, 2021 at 4:34

Oleg Melnikov

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