How to call two val: foo1 and foo2 randomly.
I managed to generate the name as a string but how can I convert it into a value name to print the value rather than the name.
val r = scala.util.Random
val foo0 = 10
val foo1 = 5
println("foo"+r.nextInt(2))
gives foo0 or foo1 when I would like 10 or 5
You can technically do this with reflection, but you shouldn't.
class Foo {
val foo0 = 10
val foo1 = 5
}
val r = new scala.util.Random
scala> val foo = new Foo
foo: Foo = Foo@f5009c7
scala> foo.getClass.getDeclaredMethod("foo" + r.nextInt(2)).invoke(foo).asInstanceOf[Int]
res19: Int = 10
Again, we shouldn't do this. It will turn your code into a sprawling mess of a minefield.
If you ever find yourself naming things with indices like foo0, foo1, foo2, etc, that means they probably belong in a collection of some type.
val foos = List(10, 5)
Then you can access them by index using apply:
foos.apply(r.nextInt(2))
scala> foos(r.nextInt(2))
res20: Int = 5
That doesn't work in a statically typed language. Pretty sure it's bad practice in any dynamic language too.
Try:
List(foo0, foo1)(r.nextInt(2))
