Password Validation regex android

Question

I need to have following password validations :

At least Min Characters 8 and Maximum Characters 15
At least One Number and 1 special characters from (! @#$%^&*-=+?.);
At least One lower case letter
Password shouldn't be sub strings of username and email (min length 3 and max length 15).
Password should be case sensitive.

I have also looked these answers but I am confuse , should I use Input filters to achieve this or Regex?

Any help will be appreciable. It will be great if you guyz provide a working solution.

Yes I tried but it isn't fulfilling my complete requirement. @WiktorStribiżew could you please help me with it. — rahul sharma
– rahul sharma, Commented Nov 28, 2016 at 8:07
Sorry, I have no idea how you can check Req. 4 with a regex. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Nov 28, 2016 at 8:08

rahul sharma · Accepted Answer · 2016-11-28 14:07:28Z

public class Validation {

    public static void main(String[] args) {  
       String pass = "1AB%CDef555";
       String username = "manna";
       String email = "[email protected]";
       System.out.println(validiate2(pass, username,email));
    }
    // if you don't care why it fails and only want to know if valid or not 
    public static boolean validiate (String pass, String username, String email){
        String pattern = "^(?=.*[0-9])(?=.*[a-z])(?=.*[!@#$%^&*+=?-]).{8,15}$";
        if(pass.matches(pattern)){
            for(int i=0;(i+3)<username.length();i++){
                if(pass.contains(username.substring(i,i+3)) || username.length()<3 || username.length()>15){
                   return false; 
                }                  
            }
            for(int i=0;(i+3)<email.length();i++){
                if(pass.contains(email.substring(i,i+3)) || email.length()<3 || email.length()>15){
                   return false; 
                }                  
            }
            return true;
        }
        return false;    
    }
    // if you want to know which requirement was not met
    public static boolean validiate2 (String pass, String username, String email){
        if (pass.length() < 8 || pass.length() >15 ){
            System.out.println("pass too short or too long");
            return false;
        }
        if (username.length() < 3 || username.length() >15 ){
            System.out.println("username too short or too long");
            return false;
        }
        if (!pass.matches(".*\\d.*")){
            System.out.println("no digits found");
            return false;
        } 

        if (!pass.matches(".*[a-z].*")) {
            System.out.println("no lowercase letters found");
            return false; 
        }
        if (!pass.matches(".*[!@#$%^&*+=?-].*")) {
            System.out.println("no special chars found");
            return false; 
        } 
        if (containsPartOf(pass,username)) {
            System.out.println("pass contains substring of username");
            return false; 
        }
        if (containsPartOf(pass,email)) {
            System.out.println("pass contains substring of email");
            return false; 
        }
        return true;           
    }

    private static boolean containsPartOf(String pass, String username) {
        int requiredMin = 3
        for(int i=0;(i+requiredMin)<username.length();i++){
            if(pass.contains(username.substring(i,i+requiredMin))){
               return true; 
            }                  
        }
        return false;        
    }    
}

makvasic · Accepted Answer · 2016-11-28 08:41:10Z

0

There is great library for that.
It's uses anotations for field and has rich customatization. I think that #4 still needs to be done by hand but you should definitly check out the library.

Here's the example from github:

@Password(min = 6, scheme = Password.Scheme.ALPHA_NUMERIC_MIXED_CASE_SYMBOLS)
private EditText passwordEditText;

Cheers.

answered Nov 28, 2016 at 8:41

makvasic

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1 Comment

rahul sharma Over a year ago

Thanks @makvasic , but I'm actually not looking for a lib to achieve this

Mustofa Rizwan · Accepted Answer · 2016-11-28 09:31:57Z

0

You can try this one:

^(?!.*(user|emailaddress))(?=.*\d)(?=.*[! @#$%^&*=+?.-])(?=.*[a-z]).{8,15}$

Make sure you replace the user and emailaddress by your variable

Explanation

This code works fine for me:

public class NewClass1 {
    public static void main(String[] args) {
        NewClass1 nc = new NewClass1();
        nc.check("abcd123-", "userName", "[email protected]");
        nc.check("userName1-", "userName", "[email protected]");
        nc.check("[email protected]", "userName", "[email protected]");
        nc.check("abcy.c1b", "userName", "[email protected]");
        nc.check("abcd123-", "userName", "[email protected]");
    }

    public void check(String string, String userName, String email) {

        final String regex = "^(?!.*(" + userName + "|" + email + "))(?=.*\\d)(?=.*[! @#$%^&*=+?.-])(?=.*[a-z]).{8,15}$";
        final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
        final Matcher matcher = pattern.matcher(string);
        if (matcher.find()) {
            System.out.println(string + "Full match: " + matcher.group(0));
        } else {
            System.out.println("no match");
        }
    }
}

edited Nov 28, 2016 at 9:31

answered Nov 28, 2016 at 8:12

Mustofa Rizwan

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5 Comments

rahul sharma Over a year ago

@Maverick_Mrt Even replacing user|emailaddress with my values, it still doesn't completing 4th point.

Mustofa Rizwan Over a year ago

@rahulsharma regex101.com/r/pN5mWQ/3 look here .. if the user name is 'user' or the email address is 'email' it doesn't match ... just tell me by editing in the link if it is working or not ... then i will look into your code

Mustofa Rizwan Over a year ago

@rahulsharma please have a look in my updated answer. having code snippet... let me know if it works for you

rahul sharma Over a year ago

Dear @maverick_Mrt there's shouldn't be substring min 3 or max 15 character , your answer works only when "user" or "email" is entered , it fails if inputs "use@1234" , see regex101.com/r/pN5mWQ/3

Mustofa Rizwan Over a year ago

in your original question you wrote, At least Min Characters 8 and Maximum Characters 15 ... moreover, use my code and append the following line ... nc.check("use@1234-", "userName", "use@1234"); it will say no match... it should say no match isn't it ?

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