How can I compare two arrays in swift which have a common element and get that element?
let a1 = [1, 2, 3]
let a2 = [4, 2, 5]
I want to compare a1 and a2 and get result 2 from comparison in swift 2.2. How?
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3stackoverflow.com/questions/25714985/…Bhavin Bhadani– Bhavin Bhadani2016-12-28 05:32:59 +00:00Commented Dec 28, 2016 at 5:32
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Check it stackoverflow.com/questions/32439289/…Amanpreet– Amanpreet2016-12-28 05:33:51 +00:00Commented Dec 28, 2016 at 5:33
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2 Answers
You can use filter function of swift
let a1 = [1, 2, 3]
let a2 = [4, 2, 5]
let a = a1.filter () { a2.contains($0) }
print(a)
print : [2]
if data is
let a1 = [1, 2, 3]
let a2 = [4, 2, 3, 5]
print : [2, 3]
If you want result in Int not in array
let result = a.first
You get optional Int(Int?) with result of first common element
7 Comments
ERbittuu
Yes, It is work for all array. condition is only both array are same type. Here is [Int] array
Md Istiak Morsalin
How can i get a not in array but simple Int?
Nirav D
@JasonBourne Is your arrays have only one common object?
Md Istiak Morsalin
Lets say it has one common object
Alexander
You should use a
Set to speed up the .contains() call. |
Another alternative would to use Sets:
let a1 = [1, 2, 3]
let a2 = [4, 2, 5]
let a = Set(a1).intersection(Set(a2)) // <- getting the element itself
print(a) // 2
let contains: Bool = !Set(a1).isDisjoint(with: Set(a2)) // <- checking if they have any common element
print(contains) // true
