10

I am using symfony 3.0 with phpUnit framework 3.7.18

Unit Test file. abcControllerTest.php

namespace AbcBundle\Tests\Controller;


use Symfony\Component\HttpFoundation\Request;
use Symfony\Bundle\FrameworkBundle\Test\WebTestCase;
use Symfony\Component\HttpFoundation\Response;

class AbcControllerTest extends WebTestCase {


    public function testWithParams() {
        $Params = array("params" => array("page_no" => 5));
        $expectedData = $this->listData($Params);

        print_r($expectedData);
    }

    private function listData($Params) {
        $client = static::createClient();        
        $server = array('HTTP_CONTENT_TYPE' => 'application/json', 'HTTP_ACCEPT' => 'application/json');
        $crawler = $client->request('POST', $GLOBALS['host'] . '/abc/list', $Params,array(), $server);
        $response = $client->getResponse();
        $this->assertSame('text/html; charset=UTF-8', $response->headers->get('Content-Type'));
        $expectedData = json_decode($response->getContent());
        return $expectedData;
    }

}

Action : abc/list

abcController.php

public function listAction(Request $request) {      
        $Params = json_decode($request->getContent(), true);
}

Code is working fine but not given expected result.Since i am trying to pass json parameter from my phpunit file abcControllerTest.php to controller abcController.php file. Anyone can suggest me how can i achieve the same things.

4 Answers 4

12

I prefer using GuzzleHttp for external requests :

use GuzzleHttp\Client;

$client = new Client();

$response = $client->post($url, [
    GuzzleHttp\RequestOptions::JSON => ['title' => 'title', 'body' => 'body']
]);

Note: GuzzleHttp should be installed with e.g. using composer.

But you can always use client bundled with Symfony:

public function testJsonPostPageAction()
{
    $this->client = static::createClient();
    $this->client->request(
        'POST', 
        '/api/v1/pages.json',  
        array(),
        array(),
        array('CONTENT_TYPE' => 'application/json'),
        '[{"title":"title1","body":"body1"},{"title":"title2","body":"body2"}]'
    );
    $this->assertJsonResponse($this->client->getResponse(), 201, false);
}

protected function assertJsonResponse($response, $statusCode = 200)
{
    $this->assertEquals(
        $statusCode, $response->getStatusCode(),
        $response->getContent()
    );
    $this->assertTrue(
        $response->headers->contains('Content-Type', 'application/json'),
        $response->headers
    );
}
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1 Comment

GuzzleHttp is for making real HTTP request, while Symfony's client simulates a browser and makes requests to a Kernel object. The latter has a lot more APIs to simplify unit testing. It also removes the need to have a web server to run the unit test.
9

A little late, but for Symfony 5, you have the jsonRequest accessible via any WebTestCase

<?php
$this->client = static::createClient();

$this->client->jsonRequest('POST', '/myJsonEndpoint', [
    'key' => 'value'
]);

Comments

1

Maybe it's a bit late... but it can help someone.

with this you can build a generic POST request and will be accepted by your controller. it's on Symfony 4.x using framework's HTTP client

use Symfony\Component\HttpFoundation\Request;

$request = new Request([], [], [], [], [], ['HTTP_CONTENT_TYPE' => 'application/json'], {"foo":"bar"}));

Comments

1

CONTENT_TYPE vs HTTP_CONTENT_TYPE

TLDR;

For Symfony 5 use this:

use Symfony\Component\HttpFoundation\Request;

$request = new Request(
    $uri, $method, $parameters, $cookies, $files,
    $server=['CONTENT_TYPE' => 'application/json'], 
    $content={"foo":"bar"})
);

Careful, for Symfony 5.2, 5.3 (maybe earlier too) code below not working:

use Symfony\Component\HttpFoundation\Request;

$request = new Request(
    $uri, $method, $parameters, $cookies, $files,
    $server=['HTTP_CONTENT_TYPE' => 'application/json'], 
    $content={"foo":"bar"})
);

Why:

  1. if no CONTENT_TYPE is set then it added to $server there
  2. then it overrides HTTP_CONTENT_TYPE there

Comments

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