code igniter :: send url as param?

Question

I am creating an ajax function to edit some settings.

these must be handled via the url

(i.e)

the url would be http://example.com/setting1/setting2/setting3

This works fine but. One of the settings is a url.

How could I pass this in this way?

You should consider switching the Ajax call to a POST request (instead of a GET request). This is simple to do in most AJAX toolkits. — Bruce Alderson
– Bruce Alderson, Commented Nov 22, 2010 at 16:11

Ross · Accepted Answer · 2010-11-22 13:54:31Z

5

this might work

$url = 'http://stackoverflow.com/questions/4245416/code-igniter-send-url-as-param';

$encoded = base64_encode($url);
//aHR0cDovL3N0YWNrb3ZlcmZsb3cuY29tL3F1ZXN0aW9ucy80MjQ1NDE2L2NvZGUtaWduaXRlci1zZW5kLXVybC1hcy1wYXJhbQ==

// Make your URL
$my_url = "site.com/controller/method/params/params/" . $encoded;

// redirect or whatever

$encoded_url = $this->uri->segment(4); // (or wherever the URL is)

$url = base64_decode($encoded_url);
// http://stackoverflow.com/questions/4245416/code-igniter-send-url-as-param

answered Nov 22, 2010 at 13:54

Ross

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1 Comment

Armen Markossyan Over a year ago

+1. This is the only way I know to do that. But of course it is better to switch to POST request.

ipalaus · Accepted Answer · 2010-11-22 12:37:44Z

0

Look for the URI Class: http://codeigniter.com/user_guide/libraries/uri.html

From index.php/user/search/name/joe/location/UK/gender/male

You can get:

[array]
(
    'name' => 'joe'
    'location'  => 'UK'
    'gender'    => 'male'
)

Using:

$array = $this->uri->uri_to_assoc(3);

You can also find useful $this->uri->segment_array() .

answered Nov 22, 2010 at 12:37

ipalaus

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3 Comments

Hailwood Over a year ago

I am aware of this. But, One of the params (lets say location is a website location) is a url you end up with ` index.php/user/search/name/joe/location/stackoverflow.com/users/383759/hailwood/gender/male` I am sure you can see the issue there...

ipalaus Over a year ago

Try with the segment_array(), you can ignore the first value if is something like /ajax/setting1/setting2. It will work.

Hailwood Over a year ago

That is not the issue. The issue is, the characters in the url are breaking it.

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