how to use $where in mongoDB javascript

Question

I'm trying to get a mongoDB document using close $where but the function return the first document in my database:

 scanCode: function (scannedcode) {
    try {

        let carItem = Cars.findOne({ $where: function () { return this.codeBarre == 'TOYOTA CAMRY      MC/ 2007CHASSIS/    509740' } });

        console.log(carItem)
        return carItem;
    }
    catch (e) {
        console.log(e.message)
    }

You can also try Cars.findOne({ codeBarre: 'TOYOTA CAMRY MC/ 2007CHASSIS/ 509740' }); or Cars.find({ codeBarre: 'TOYOTA CAMRY MC/ 2007CHASSIS/ 509740' }).fetch(); — chridam
– chridam, Commented Feb 27, 2017 at 9:00

Avindu Hewa · Accepted Answer · 2017-02-27 09:03:23Z

2

EDITED

scanCode: function (scannedcode) {
try {

    let carItem = Cars.findOne({ $where: "this.codeBarre == 'TOYOTA CAMRY      MC/ 2007CHASSIS/    509740'" });

    console.log(carItem)
    return carItem;
}
catch (e) {
    console.log(e.message)
}

edited Feb 27, 2017 at 9:03

answered Feb 27, 2017 at 8:33

Avindu Hewa

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10 Comments

Avindu Hewa Over a year ago

@sana so im guessing the logical expression your using is is wrong

sana Over a year ago

i don't think so :/

Avindu Hewa Over a year ago

can you explain your goal out of this query ?@sana

Avindu Hewa Over a year ago

Cars.findOne({ $where: "this.codeBarre == 'TOYOTA CAMRY MC/ 2007CHASSIS/ 509740' "}); have you tried this method

sana Over a year ago

how can i pass 'scannedcode' as un args insted of 'TOYOTA CAMRY MC/ 2007CHASSIS/ 509740' ??

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