Python multi-instances use the same variable

Question

I want to use a variable for two instances in python. When a instance update the variable, it also be updated in other instances.

my variable is task_id:

class Task(object):     # pragma: no cover

    def run_deploy(self, args, **kwargs):
        # atexit.register(atexit_handler)
        self.task_id = kwargs.get('task_id', str(uuid.uuid4()))

    def start_benchmark(self, args, **kwargs):
        """Start a benchmark scenario."""
        atexit.register(atexit_handler)

        self.task_id = kwargs.get('task_id', str(uuid.uuid4()))

But when I run code, I detected that task_id has different value, I want they have same value.

Please let me know how to do it. Thanks!

To understand what happens and how things work in Python, see for example nedbatchelder.com/text/names1.html — Thierry Lathuille
– Thierry Lathuille, Commented Feb 27, 2017 at 10:13
Can you put some code in so I can see what you want to happen please? — The Stupid Engineer
– The Stupid Engineer, Commented Feb 27, 2017 at 10:19
I asked a question in following url: stackoverflow.com/questions/42477885/…, you can look at some code in that url. thanks! — Toandd
– Toandd, Commented Feb 27, 2017 at 10:26

prometeu · Accepted Answer · 2017-08-28 08:58:14Z

3

To reference an object in python is trivial. Here is a simple example using a class instance:

class cl:
  var1 = 0
  def __init__(self, var2):
    self.var2 = var2

Lets look at two instances of this class and how they update:

>>> x = cl(1) #
>>> y=x
>>> print(y.var2)
1
>>> y.var2 = 2
>>> print(x.var2)
2

And now comes the crucial part:

>>> x is y
True

Don't forget that ìs is not the same as ==.

The same happens also to var1 for both instances.

edited Aug 28, 2017 at 8:58

answered Feb 27, 2017 at 10:57

prometeu

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Comments

shx2 · Accepted Answer · 2017-02-27 10:14:18Z

1

In python, everything is a reference. A variable is merely a name you give to a reference to an object. You can give many names to refer to the same object.

This pretty much how python works, and it's exactly what you need here.

E.g.:

a = []  # a reference to an empty list, named "a"
b = a   # a reference to the same empty list, named "b"
a.append(5)  # modify, through the "a" reference
print(b)  # "b" still refers to the same list, which is not empty now
=> [5]

answered Feb 27, 2017 at 10:14

shx2

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