How to add string to a url in php?

Question

I have a random string using a php function I found here

<?php function generateRandomString($length = 12) {
    $characters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
    $charactersLength = strlen($characters);
    $randomString = '';
    for ($i = 0; $i < $length; $i++) {
        $randomString .= $characters[rand(0, $charactersLength - 1)];
    }
    $randomString;
}

$randomString = generateRandomString(); ?>

I have a form

<form method="post" id="form" action="<?php bloginfo('url'); ?>/results/">
    <input type="text" name="height" placeholder="Enter height">
    <input type="text" name="weight" placeholder="Enter weight">
    <input type="submit" id="export">
</form>

When you click submit it takes you to the .com/results/ page but i am trying to change /results/ to the random string from the generateRandomString function and still show the content that would have been shown on the results page

To do this so far i have tried adding this jQuery under the form

$("#export").click(function(){
    url = $("#form").attr("action");
    url = url.replace("/results/",<?php echo $randomString ?>);
    $("#form").attr("action", url).submit();
});

but that still doesn't work. Does anyone know how another way i could do this please?

Thank you

the php file below-

    <script src="jquery-3.1.1.min.js"></script>
<?php function generateRandomString($length = 12) {
    $characters =     '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
    $charactersLength = strlen($characters);
    $randomString = '';
    for ($i = 0; $i < $length; $i++) {
        $randomString .= $characters[rand(0, $charactersLength - 1)];
    }
    return $randomString;
}
$randomString = generateRandomString();
?>

<form method="post" id="form" action="<?php bloginfo('url'); ?>/results/">
    <input type="text" name="height" placeholder="Enter height">
    <input type="text" name="weight" placeholder="Enter weight">
    <input type="submit" id="export">
</form>

<script>
$("#export").click(function(){
  url = $("#form").attr("action");
  url = url.replace("/results/",<?php echo $randomString ?>);
  $('#form').attr('action', url).submit();
});
</script>

try url = url.replace("/results/","<?php echo $randomString ?>"); — Alex Odenthal
– Alex Odenthal, Commented Mar 1, 2017 at 11:28
@AlexOdenthal that still takes you to /results/. It does give an error saying $ is not defined in console, but I put in script tags (it's in php file) and added jQuery library - don't know why it still say that — Himmat
– Himmat, Commented Mar 1, 2017 at 11:35
/results/ is a wordpress page that gets its contents from results.php file. I have it kind of working now!! It will return mydomain.com/random BUT it 404 and says the page isnot found. Any idea how i can send content from results.php to the new url? — Himmat
– Himmat, Commented Mar 1, 2017 at 12:33

Dan Ionescu · Accepted Answer · 2017-03-01 11:28:46Z

2

Your function does not return a value, use return statement:

 function generateRandomString($length = 12) {
    $characters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
    $charactersLength = strlen($characters);
    $randomString = '';
    for ($i = 0; $i < $length; $i++) {
         $randomString .= $characters[rand(0, $charactersLength - 1)];
    }

    return $randomString;
}

answered Mar 1, 2017 at 11:28

Dan Ionescu

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1 Comment

Himmat Over a year ago

even with return it still doesnot replace, i have added the php code so you can see

Mithu CN · Accepted Answer · 2017-03-01 12:28:29Z

1

  <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.1.1/jquery.js"></script>

<?php
 function generateRandomString($length = 12) {
    $characters =     '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
    $charactersLength = strlen($characters);
    $randomString = '';
    for ($i = 0; $i < $length; $i++) {
        $randomString .= $characters[rand(0, $charactersLength - 1)];
    }
    return $randomString;
}
$randomString = generateRandomString();
?>
  <form method="post" id="form" action="google.com/results/">
    <input type="text" name="height" placeholder="Enter height">
    <input type="text" name="weight" placeholder="Enter weight">

</form>
 <input type="submit" id="export">


<script>
$("#export").click(function(event){
  url = $("#form").attr("action");
  url = url.replace("results/","<?php echo $randomString ?>");
  console.log(url);
 //event.preventDefault();
  $('#form').attr('action', url).submit();
});
</script>

edited Mar 1, 2017 at 12:28

answered Mar 1, 2017 at 11:31

Mithu CN

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6 Comments

Himmat Over a year ago

please see the update, still does not work with return in function

Mithu CN Over a year ago

you have to write php code in java script using " ". So replace url.replace("/results/",<?php echo $randomString ?>); with url.replace("/results/","<?php echo $randomString ?>");

Himmat Over a year ago

I appreicate your help sir, but that still just goes to /results/. i am getting these console errors: GET domain.com/jquery-3.1.1.min.js and Uncaught TypeError: $ is not a function. Maybe that is causing the problem?

Mithu CN Over a year ago

I executed those code but i didn't get any error . whatever see the update code and run on your server .

Himmat Over a year ago

I have it kind of working now thanks to you! it is going to mydomain.com/randomString after i click it, but it says the page isnot found. Do you know how i could still send the content from /results/ page (results.php) to the new url?

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