Python regular expression replace date

Question

I have string like this

INPUT:

date = '2017-02-03 14:07:03.840'

And how replace 2017-02-03 In order to on output I'll have

2017-02-03 14:07:03.840 => 2015-01-01 14:07:03.840

How to replace only date without time? Using re module

\d{4}-\d{1,2}-\d{1,2}?

Aran-Fey
– Aran-Fey

2017-03-04 13:22:04 +00:00
Commented Mar 4, 2017 at 13:22 — Aran-Fey
– Aran-Fey, Commented Mar 4, 2017 at 13:22

m87 · Accepted Answer · 2017-03-04 13:23:54Z

4

You can use the following regex to select only the date and by substituting it with your desired date you can get the expected result :

\d{4}-\d{2}-\d{2}

python

import re
regex = r"\d{4}-\d{2}-\d{2}"
date = "2017-02-03 14:07:03.840"
subst = "2015-01-01"
result = re.sub(regex, subst, date, 0)
if result:
    print (result)

answered Mar 4, 2017 at 13:23

m87

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2 Comments

user5639219 Over a year ago

How I can replace time in the new string? 14:07:03.840

m87 Over a year ago

@Maic use this regex \d+:\d+:[\d.]+

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