call a function in Python syntax

Question

Hey im writing a small program in python 2.6 and i have defined 2 helper functions which does almost all i want, for instance

def helper1:
    ...


def helper2:
    ...

Now my problem is that i want to make a new function that gather the two functions in one function so i dont have to write (in shell):

list(helper1(helper2(argument1,argument2)))

but instead just

function(argument1,argument2)

Is there any short way around that? Im all new to python, or do you need more code-sample to be able to answer?

Thanx in advance for any hints or help

Tim Pietzcker · Accepted Answer · 2010-11-25 09:59:22Z

8

def function(arg1, arg2):
    return list(helper1(helper2(arg1, arg2)))

should work.

answered Nov 25, 2010 at 9:59

Tim Pietzcker

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Ignacio Vazquez-Abrams · Accepted Answer · 2010-11-25 09:59:29Z

2

function = lambda x, y: list(helper1(helper2(x, y)))

answered Nov 25, 2010 at 9:59

Ignacio Vazquez-Abrams

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Gareth Rees · Accepted Answer · 2010-11-26 20:10:23Z

2

This is an example of the higher order function compose. It's handy to have laying around

def compose(*functions):
    """ Returns the composition of functions"""
    functions = reversed(functions)
    def composition(*args, **kwargs):
        func_iter = iter(functions)
        ret = next(func_iter)(*args, **kwargs)
        for f in func_iter:
            ret = f(ret)
        return ret
    return composition

You can now write your function as

function1 = compose(list, helper1, helper2)
function2 = compose(tuple, helper3, helper4)
function42 = compose(set, helper4, helper2)

etc.

edited Nov 26, 2010 at 20:10

Gareth Rees

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answered Nov 25, 2010 at 10:13

aaronasterling

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