Example user input
http://example.com/
http://example.com/topic/
http://example.com/topic/cars/
http://www.example.com/topic/questions/
I want a PHP function to make the output like
example.com
example.com/topic/
example.com/topic/cars/
www.example.com/topic/questions/
ereg_replace is now deprecated, so it is better to use:
$url = preg_replace("(^https?://)", "", $url );
This removes either http:// or https://
"^[a-zA-Z0-9]+://" instead
You should use an array of "disallowed" terms and use strpos and str_replace to dynamically remove them from the passed-in URL:
function remove_http($url) {
$disallowed = array('http://', 'https://');
foreach($disallowed as $d) {
if(strpos($url, $d) === 0) {
return str_replace($d, '', $url);
}
}
return $url;
}
http://domain.com/topic/https://more/? That's a valid url with a valid path, but this approach would mangle it in a way that (I think) the OP wouldn't have intended.
I'd suggest using the tools PHP gave you, have a look at parse_url.
<?php
$url = 'http://username:password@hostname/path?arg=value#anchor';
print_r(parse_url($url));
echo parse_url($url, PHP_URL_PATH);
?>
The above example will output:
Array
(
[scheme] => http
[host] => hostname
[user] => username
[pass] => password
[path] => /path
[query] => arg=value
[fragment] => anchor
)
/path
It sounds like you're after at least host + path (add others as needed, e.g. query):
$parsed = parse_url('http://www.domain.com/topic/questions/');
echo $parsed['host'], $parsed['path'];
> www.domain.com/topic/questions/
Cheers
Create an array:
$remove = array("http://","https://");
and replace with empty string:
str_replace($remove,"",$url);
it would look something like this:
function removeProtocol($url){
$remove = array("http://","https://");
return str_replace($remove,"",$url);
}
Str_replace will return a string if your haystack (input) is a string and you replace your needle(s) in the array with a string. It's nice so you can avoid all the extra looping.
Wow. I came here from google expecting to find a one liner to copy and paste!
You don't need a function to do this because one already exists. Just do:
echo explode("//", "https://anyurl.any.tld/any/directory/structure", 2)[1];
In this example, explode() will return an array of:
["https:", "anyurl.any.tld/any/directory/structure"]
And we want the 2nd element. This will handle http, https, ftp, or pretty much any URI, without needing regex.
https://www.php.net/manual/en/function.explode.php
If you want a function:
function removeProtocols($uri) { return explode("//", $uri, 2)[1]; }
EDIT: See user comment from Harry Lewis... this is my favourite way to do this now.
explode()'s 3rd argument, $limit like so: explode('//', $url, 2);
last(explode('//', $url, 2));You can remove both https and http in one line using a regular expression with preg_replace:
fn (string $url): string
=> preg_replace('~^https?://~', '', $url);
~^https?://~ Test and Explanation (regex101.com)You could use the parse url Functionality of PHP. This will work for all Protocols, even ftp:// or https://
Eiter get the Protocol Component and substr it from the Url, or just concatenate the other Parts back together ...
<?php
// user input
$url = 'http://www.example.com/category/website/wordpress/wordpress-security/';
$url0 = 'http://www.example.com/';
$url1 = 'http://www.example.com/category/';
$url2 = 'http://www.example.com/category/website/';
$url3 = 'http://www.example.com/category/website/wordpress/';
// print_r(parse_url($url));
// echo parse_url($url, PHP_URL_PATH);
$removeprotocols = array('http://', 'https://');
echo '<br>' . str_replace($removeprotocols,"",$url0);
echo '<br>' . str_replace($removeprotocols,"",$url1);
echo '<br>' . str_replace($removeprotocols,"",$url2);
echo '<br>' . str_replace($removeprotocols,"",$url3);
?>
