0 
#include<conio.h>
#include<stdio.h>
void main()
{
    int i=0;
    char s[]={"this is string"};
    while(s[i]!=0)
    {
        printf("%c",i[s]);
        i++;
    }
}

This Program does not give error and produce output as "this is string". why..??

Improve this question
3
  • 4
    s[i] and i[s] are same as *(s + i). Commented Apr 27, 2017 at 11:39
  • 1
    Short answer: don't write weird crap like that and you don't have to worry about why it works. Knowing that you can change the place of the s and i is useless knowledge. Commented Apr 27, 2017 at 11:49
  • Please format your code (like in your C textbook). Commented Apr 27, 2017 at 12:20
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