Lets Say we have Zaptoit:685158:[email protected]
How do you split so it only be left 685158:[email protected]
Add a comment
|
7 Answers
>>> s = 'Zaptoit:685158:[email protected]'
>>> s.split( ':', 1 )[1]
'685158:[email protected]'
1 Comment
Jay
Note that it's not really good practice to use the variable name "str" since str() is a builtin.
Another solution:
s = 'Zaptoit:685158:[email protected]'
s.split(':', 1)[1]
answered Jan 12, 2009 at 19:15
Federico A. Ramponi
47.2k31 gold badges113 silver badges134 bronze badges
Comments
Another method, without using split:
s = 'Zaptoit:685158:[email protected]'
s[s.find(':')+1:]
Ex:
>>> s = 'Zaptoit:685158:[email protected]'
>>> s[s.find(':')+1:]
'685158:[email protected]'
Comments
As of Python 2.5 there is an even more direct solution. It degrades nicely if the separator is not found:
>>> s = 'Zaptoit:685158:[email protected]'
>>> s.partition(':')
('Zaptoit', ':', '685158:[email protected]')
>>> s.partition(':')[2]
'685158:[email protected]'
>>> s.partition(';')
('Zaptoit:685158:[email protected]', '', '')
1 Comment
Nick K9
This is exactly what I was looking for. I knew about
split(), but hadn't run across partition() before. Thanks!Following splits the string, ignores first element and rejoins the rest:
":".join(x.split(":")[1:])
Output:
'685158:[email protected]'
Comments
s = re.sub('^.*?:', '', s)
7 Comments
orip
@PEZ: better being stopping the match on the first ':' instead of the last one
Arkady
@orip: I think you are mistaken -- the question mark makes it a non-greedy match that will stop at the first colon, as intended
PEZ
Yeah, I think Nick means something else.
Alan Moore
It doesn't matter in this case, but in general, if you have choice between a negated character class and a reluctant quantifier (eg, '.*?'), the char class tends to be faster, less memory-intensive, and most importantly, more predictable.
Samuel Lampa
Sorry, forgot to compile the regexes outside the for loop. When doing this, the negated character class version takes 34% less time. I also tried to compile the code with cython, statically declaring the int:s and double:s (which should reduce overhead). Then time is reduced by 40%, so the negated character class clearly is faster.
|
Use the method str.split() with the value of maxsplit argument as 1.
mailID = 'Zaptoit:685158:[email protected]'
mailID.split(':', 1)[1]
Hope it helped.
